Question

我正在尝试在我的Android应用程序中实现搜索功能，我想从活动发现中获取用户在搜索编辑文本中写入的内容，并打开一个名为活动搜索的新活动，其中结果可以显示，发布object是我的一个实现类，我从后端获取数据每次我尝试它都会抛出一个异常这是我为此部分的Activity发现的代码 `

search.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {

        }

        @Override
        public void afterTextChanged(Editable s) {
            // setContentView(R.layout.search_grid);
            // gridView2 = (GridView) findViewById(R.id.search_grid);
            RequestParams rp = new RequestParams();
            final String url;
            if (people.isChecked()) {
                rp.add("user", search.getText().toString());
                rp.add("counter", "");
                url = "search_users";
            } else if (tags.isChecked()) {
                rp.add("tag", search.getText().toString());
                rp.add("counter", "");
                url = "search_exact_hashtag";
            } else {
                rp.add("location", search.getText().toString());
                rp.add("counter", "");
                url = "search_location";
            }
            final ArrayList<PostObject> addyExtras = new ArrayList<>();
            //Toast.makeText(getApplicationContext()," something " + , Toast.LENGTH_SHORT).show();
            PabloClient.post(url, rp, new JSONHandler(getApplicationContext(), new JSONHandler.OnFinishedListener() {
                @Override
                public void OnFinished(int statusCode, Header[] headers, JSONObject response, int result) {
                    try {
                        if (result == 1) {
                            // Toast.makeText(getApplicationContext(), response.toString(), Toast.LENGTH_SHORT).show();

                            JSONArray posts = response.getJSONArray("data");
                            setContentView(R.layout.search_grid);
                            //////////////////////////////////////////////


                            //////////////////////////////////////////////////////////////////
                            for (int i = 0; i < posts.length(); i++) {
                                searchPosts.add(new PostObject(posts.getJSONObject(i)));


                                addyExtras.add(searchPosts.get(i));

                            }




                        }
                    } catch (JSONException e) {
                        e.printStackTrace();

                    }
                    Intent intent = new Intent(ActivityDiscover.this, ActivitySearch.class);
                    intent.putParcelableArrayListExtra("mylist", addyExtras);
                    startActivity(intent);

                }
            }));
        }

    });

`

以及我如何获得搜索活动的意图

searchPosts2 = getIntent().getParcelableArrayExtra("mylist");

Answer 1

PostObject类中的

执行以下操作....

   public class PostObject implements Parcelable 
   {

      ///......your class code


@Override
public int describeContents() {
    return 0;
}

@Override
public void writeToParcel(Parcel dest, int flags) {

}

public PostObject(Parcel in) {
    super();
//    readFromParcel(in);
}

public static final Parcelable.Creator<PostObject> CREATOR = new Parcelable.Creator<PostObject>() {
    public PostObject createFromParcel(Parcel in) {
        return new PostObject(in);
    }

    public PostObject[] newArray(int size) {

        return new PostObject[size];
    }

};

}

Answer 2

应在Bundle

的帮助下传递数组

发送数组

从发件人方面开始，您需要在捆绑包中添加阵列列表

Bundle data = new Bundle();
data.putParcelableArrayList("mylist", addyExtras);

然后将捆绑包添加到Intent

 Intent intent = new Intent(ActivityDiscover.this, ActivitySearch.class);
    intent .putExtra("content", data);
    startActivity(yourIntent);

Retrive Array

在接收方结束时从意图

获取捆绑包

Bundle data =  getIntent().getBundleExtra("content");

然后从bundle

获取数组列表

searchPosts2  =  data.getParcelableArrayList("mylist");

通过意图将编辑文本的文本移动到另一个活动会引发异常

2 个答案: