Question

我得到一个函数作为函数参数，并希望在#selector中设置它。但我收到错误消息：

Argument of '#selector' cannot refer to a property

我有以下功能：

private func addGestureRecognizerToItem(selector: () -> ()) {
        let labelGesture = UITapGestureRecognizer(target: self, action: #selector(selector))
        let imageGesture = UITapGestureRecognizer(target: self, action: #selector(selector))
        label.addGestureRecognizer(labelGesture)
        imageView.addGestureRecognizer(imageGesture)
}

任何想法如何处理？

Answer 1

这个怎么样？

class ViewController: UIViewController {

let label = UILabel()
let imageView = UIImageView()

override func viewDidLoad() {
    super.viewDidLoad()

    addGestureRecognizerToItem(#selector(test))
}

func test() {
}

private func addGestureRecognizerToItem(selector: Selector) {
    let labelGesture = UITapGestureRecognizer(target: self, action: selector)
    let imageGesture = UITapGestureRecognizer(target: self, action: selector)
    label.addGestureRecognizer(labelGesture)
    imageView.addGestureRecognizer(imageGesture)
}

}

Answer 2

这是不可能的，相反，您可以从第一个函数的返回调用您想要的函数，该函数的数据要传递给另一个函数。您的情况可能会根据您的要求而改变。

将函数传递给#selector

2 个答案: