Question

我遇到查询问题（MS SQL Server），我想知道是否可以执行以下操作以及如何正确执行此操作。

这是查询：

select numTenants, count(codSite) numSites
from (select case count(st1.name) when 0 then '0T'
                       when 1 then '1T' 
                       when 2 then '2T' 
                       when 3 then '3T'
                       when 4 then '4T'
                       else 'More than 4T' end numTenants, os1.siteCode as codSite
    from fl_OperativeSite os1 left join fl_SiteTenant st1
        on st1.fkOperativeSite=os1.pkOperativeSite
    where  os1.siteType='A' and os1.externalInfrastructure=2
    group by os1.siteCode) groups
group by numTenants
order by numTenants

这就是结果：

numTenants     numSites
   1T             2957
   2T              553
   3T             1503
   4T              423
More than 4T       131

因为很明显没有一个“网站”，其中0为numTenants。

我想问的是：有没有办法让结果显示如下？

numTenants     numSites
   0T                0
   1T             2957
   2T              553
   3T             1503
   4T              423
More than 4T       131

非常感谢！

Answer 1

这很简单：选择所有＆＃34;数字＆＃34;和外部加入您的查询：

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        <h1>Hello world!</h1>
    </body>
</html>

Answer 2

假设您自己的查询工作正常。创建一个表变量。

declare @tbl table(numTenants varchar(50))
insert into @tbl values ('0T'), ('1T'),('2T'),('3T'),('4T'),('More than 4T')

;With CTE As
(
 select numTenants, count(codSite) numSites
from (select case count(st1.name) when 0 then '0T'
                       when 1 then '1T' 
                       when 2 then '2T' 
                       when 3 then '3T'
                       when 4 then '4T'
                       else 'More than 4T' end numTenants, os1.siteCode as codSite
    from fl_OperativeSite os1 left join fl_SiteTenant st1
        on st1.fkOperativeSite=os1.pkOperativeSite
    where  os1.siteType='A' and os1.externalInfrastructure=2
    group by os1.siteCode) groups
group by numTenants
order by numTenants
)

select a.numTenants,isnull(s.numSites,0) numSites from @tbl A 
left join CTE S on a.numTenants=s.numTenants

显示非结果行SQL（groupby - count）

2 个答案: