Question

我很难编写代码的某些部分。我有一个detailData数组，用于保存其他对象。

    var detailData = [];

    detailData[0] = {
        "Detail1": null, "Detail2": null, "Detail3": null, "Detail4": null, "Detail5": null,
        "RequestTrackingId1": null, "RequestTrackingId2": null, "RequestTrackingId3": null, "RequestTrackingId4": null,
        "RequestTrackingId5": null, "header": "Request Tracking Id"
    }

    detailData[1] = {
        "Detail1": null, "Detail2": null, "Detail3": null, "Detail4": null, "Detail5": null,
        "RequestTrackingId1": null, "RequestTrackingId2": null, "RequestTrackingId3": null, "RequestTrackingId4": null,
        "RequestTrackingId5": null, "header": "Source System Code"
    }

    detailData[2] = {
        "Detail1": null, "Detail2": null, "Detail3": null, "Detail4": null, "Detail5": null,
        "RequestTrackingId1": null, "RequestTrackingId2": null, "RequestTrackingId3": null, "RequestTrackingId4": null,
        "RequestTrackingId5": null, "header": "Source System UId"
    }

因此每个detailData对象都将包含detail1，detail2，detail3等。

现在从另一个数组我想为它们分配如下值：

        for (var i = 0; i < $scope.arc_srcsys_cds.length; i++) {
            var detailIndex = "Detail" + (i + 1);
            detailData[1].detailIndex = $scope.arc_srcsys_cds[i];
        }

但它没有为detail1,detail2分配值，依此类推。而是创建另一个名为detailIndex的字段。

如何达到预期效果？

Answer 1

你可以试试这个：

detailData[i][detailIndex] = $scope.arc_srcsys_cds[i];
// detailData[1] will only replace or second array not for all

Answer 2

尝试：

    for (var i = 0; i < $scope.arc_srcsys_cds.length; i++) {
        var detailIndex = "Detail" + (i + 1);
        detailData[i][detailIndex] = $scope.arc_srcsys_cds[i];
    }

Javascript或角度js

2 个答案: