Question

我是PHP和Codeigniter的新手，我正在开发一个小型的婚姻网站应用程序。

事实是，我有一个用简单的PHP编写的SQL查询，现在我正在寻找的是与Codeigniter风格相同的SQL查询。

以下是普通的SQL查询，需要以Codeigniter样式编写。

SELECT 
    *
FROM
    users
WHERE
    IF('$se_ct' != '',
        sect = '$se_ct'
            AND IF('$subsect' != '',
            subsect = '$subsect',
            subsect LIKE '%%'),
        sect LIKE '%%' AND subsect LIKE '%%')
        AND IF('$coun_try' != '',
        country = '$coun_try'
            AND IF('$sta_te' != '',
            state = '$sta_te'
                AND IF('$ci_ty' != '',
                city = '$ci_ty',
                city LIKE '%%'),
            state LIKE '%%' AND city LIKE '%%'),
        country LIKE '%%' AND state LIKE '%%'
            AND city LIKE '%%')
        AND age >= '$age_from'
        AND age <= '$age_to'
        AND IF('$qualification' != '',
        qualification = '$qualification',
        qualification LIKE '%%')
        AND gender = '$look'
        AND status = '1'

感谢帮助者，指导者和开发者。

Answer 1

你也可以在codeigniter

中使用它

    $this->db->query("SELECT *
    FROM users
    WHERE  
    if('$se_ct'!='',sect =  '$se_ct'
    AND 
    if('$subsect' !='',subsect =  '$subsect',subsect like  '%%'),
    sect like  '%%' AND subsect like  '%%')
    AND
    IF( '$coun_try' !='', country =  '$coun_try'
    AND 
    if('$sta_te' !='', state =  '$sta_te'
    AND  
    if('$ci_ty' !='',city =  '$ci_ty',city like  '%%'),state LIKE  '%%'
    AND city LIKE  '%%'), country LIKE  '%%'
    AND state LIKE  '%%'
    AND city LIKE  '%%' ) 
    AND age >=  '$age_from'
    AND age <=  '$age_to'
    AND 
    IF('$qualification' !='',qualification =  '$qualification',  qualification LIKE  '%%' ) 
    AND gender =  '$look'
    And status='1'");

   //for echo the last executed query 
    $this->db->last_query();


   //for returning the result from model to controller     
    return $query->result_array();

Answer 2

您可以使用这些纯Codeigniter： -

Codeigniter模型代码： -

function get_result()
{
    $this->db->select('*');
    if ($se_ct != "")
    {
        $this->db->where('sect', $se_ct); 
        if ($subsect != "")
        {
            $this->db->where('subsect', $subsect);  
        }
        else
        {
            $this->db->like('subsect', "");     
        }
    }

    if($coun_try != "")
    {
        $this->db->where('coutry', $count_try); 
        if ($sta_te != "")
        {
            $this->db->where('state', $sta_te);         
            if ($ci_ty != "")
            {
                $this->db->where('city', $ci_ty);               
            }
            else
            {
                $this->db->like('city', ""); 
            }
        }   
        else
        {
            $this->db->like('state', ""); 
        }
    }
    else
    {
        $this->db->like('country', ""); 
    }


    $this->db->where(array('age >=' => $age_from, 'age <=' => $age_to));

    if ($qualification != "")
    {
        $this->db->where('qualification', $qualification); 
    }
    else
    {
        $this->db->like('qualification', ""); 
    }

    $this->db->where('gender', $look); 
    $this->db->where('status', 1); 

    $this->db->from('users');

    return $this->db->get();
}

Codeigniter控制器的代码： -

$data['user'] = $this->user_model->get_result(); // take model as per your code

$this->load->view('user', $data); // take view file as per your code

Answer 3

您可以按如下方式编写查询

return $this->db->query("SELECT * FROM users
WHERE  
if('$se_ct'!='',sect =  '$se_ct'
AND 
if('$subsect' !='',subsect =  '$subsect',subsect like  '%%'),
sect like  '%%' AND subsect like  '%%')
AND
IF( '$coun_try' !='', country =  '$coun_try'
AND 
if('$sta_te' !='', state =  '$sta_te'
AND  
if('$ci_ty' !='',city =  '$ci_ty',city like  '%%'),state LIKE  '%%'
AND city LIKE  '%%'), country LIKE  '%%'
AND state LIKE  '%%'
AND city LIKE  '%%' ) 
AND age >=  '$age_from'
AND age <=  '$age_to'
AND 
IF('$qualification' !='',qualification =  '$qualification',  qualification LIKE  '%%' ) 

AND gender =  '$look'

And status='1'")->result();

Codeigniter sql查询已经在核心php

3 个答案: