Question

以下是源文件中的数据：

 {
 "dubbuseqchapter+block@a7a5931f68d0482eaff2b7c9f9684e47": {
    "category": "chapter", 
    "children": [
      "dubbuseqsequential+block@968513c8f0cc4249b7cfc2290ac967dc", 
      "dubbuseqsequential+block@f7f730a478144a74bd127f996d6dc4f5", 
      "dubbuseqsequential+block@91a0d5d7cd9649a3bdf057400e0a1c96", 
      "dubbuseqsequential+block@28b2b171b6734b13af29735796c5ad5a", 
      "dubbuseqsequential+block@192a150c8aab43b9bd236773ba60b414", 
      "dubbuseqsequential+block@26b3464dad42460ea66f9afe89770065"
    ], 
    "metadata": {
      "display_name": "Introduction course orientation"
    }
  }, 


  "dubbuseqchapter+block@b2451e9195c5466db8b66f53ed06c9fd": {
    "category": "chapter", 
    "children": [
      "dubbuseqsequential+block@c95826a16f71405ba58319d23d250fc4", 
      "dubbuseqsequential+block@fe4e3b8b7cdd4fa0b9fe9090223b7125", 
      "dubbuseqsequential+block@44bbdee625dc465ebe725d2126ed0662", 
      "dubbuseqsequential+block@8d4daba07d4443f3b2a0b2506280ee2c", 
      "dubbuseqsequential+block@c68d9d3ba7de45b1b0770085e4f1f286", 
      "dubbuseqsequential+block@ccdca5b2aca94dbdabb3a57a75adf3fa"
    ], 
    "metadata": {
      "display_name": "Module closing section"
    }
    }
    }

以下javascript带来了顶级键值（即dubbuseqchapter + block @ a7a5931f68d0482eaff2b7c9f9684e47，dubbuseqchapter + block @ b2451e9195c5466db8b66f53ed06c9fd）

Javascript代码

    var obj = JSON.parse(jContent);
        var keys = Object.keys(obj);


    for (var i = 0; i < keys.length; i++) {
        var row = createRowCopy(getOutputRowMeta().size());
        var idx = getInputRowMeta().size();


            row[idx++] = keys[i];

        //  Alert (keys.length);

            putRow(row);
        }

但是，在这个例子中，我无法获得密钥的值..（即类别，子元素和元数据）。

我尝试过Objects.values（）但它在Alert中返回null或object对象。

Answer 1

keys是一个字符串数组，每个字符串都是属性名。

您可以通常的方式获取属性名称的值：

object[property_name]

即

var value = obj[keys[i]];

Answer 2

此代码显示如何导航到已解析的JsonData

var obj = JSON.parse(textJson);
var keys = Object.keys(obj);
console.log(obj[keys[0]].metadata.display_name);

这将打印：简介课程方向

Answer 3

甚至可以通过这种方式检索您的subProperties

var obj = JSON.parse(textJson);
var keys = Object.keys(obj);
for (var i = 0; i < keys.length; i++){
  console.log(keys[i]);
  var subKeys = Object.keys(obj[keys[i]]);
  for (var j = 0; j < subKeys.length; j++) console.log(subKeys[j] + " --> " + obj[keys[i]][subKeys[j]]);
}

Javascript只返回键而不返回值

3 个答案: