我目前正在使用数据库,但我遇到了一个选择查询。 但是,我不是数据库专家。 查询应该从具有多对多关系的表中返回数据。
这是我的表格图表,它将显示我的问题的概念
选择查询应该查看三个列,即VidTbl.Name,ActorTbl.Name和SubTitelTbl.name。
所以,我已经在互联网上阅读和搜索,并且我已经尝试了
首先尝试
SELECT
VidTbl.NAME AS Video_Titel_Name,
ActorTbl.NAME AS Actor_Name
FROM ActorInVid
INNER JOIN VidTbl
ON VidTbl.Id = ActorInVid.FKVidId
INNER JOIN ActorTbl
ON ActorTbl.Id = ActorInVid.FKActorId
UNION all
SELECT
VidTbl.NAME AS Video_Titel_Name,
SubTitelTbl.NAME AS SubTitel_Langu
FROM SubTitelInVid
INNER JOIN VidTbl
ON VidTbl.Id = SubTitelInVid.FKVidId
INNER JOIN SubTitelTbl
ON SubTitelTbl.Id = SubTitelInVid.FKSTId
结果我得到了,这是错误的
然后我尝试了另一种方法来解决这个问题,但我又遇到了另一个错误
第二次尝试
SELECT Temp1.*
From (SELECT VidTbl.Id AS Video_Id,
VidTbl.NAME AS Video_Titel_Name,
ActorTbl.NAME AS Actor_Name
FROM ActorInVid
INNER JOIN VidTbl
ON VidTbl.Id = ActorInVid.FKVidId
INNER JOIN ActorTbl
ON ActorTbl.Id = ActorInVid.FKActorId) AS Temp1
SELECT Temp2.*
FROM (SELECT VidTbl.Id AS Video_Id,
SubTitelTbl.NAME AS SubTitel_Langu
FROM SubTitelInVid
INNER JOIN VidTbl
ON VidTbl.Id = SubTitelInVid.FKVidId
INNER JOIN SubTitelTbl
ON SubTitelTbl.Id = SubTitelInVid.FKSTId) AS Temp2
SELECT *
FROM VidTbl
INNER JOIN Temp1
on Temp1.Video_Id = VidTbl.Id
INNER JOIN Temp2
on Temp2.Video_Id = VidTbl.Id
错误,我在最后一次选择错误
非常感谢你的帮助 我希望我的问题清楚而有用 再次感谢。
答案 0 :(得分:1)
你很亲密。这应该有用......
SELECT
VidTbl.Name,
ActorTbl.Name,
SubTitelTbl.name
FROM VidTbl
INNER JOIN ActorInVid ON VidTbl.Id = ActorInVid.FKVidId
INNER JOIN ActorTbl ON ActorTbl.Id = ActorInVid.FKActorId
INNER JOIN SubTitelInVid ON VidTbl.Id = SubTitelInVid.FKVidId
INNER JOIN SubTitelTbl ON SubTitelTbl.Id = SubTitelInVid.FKSTId
答案 1 :(得分:0)
SELECT DISTINCT vt.Name, at.Name, st.Name
FROM VidTbl vt
JOIN ActionInVid aiv ON aiv.VidId = vt.Id
JOIN SubtitleInVid siv ON siv.VidId = vt.Id
JOIN ActorTbl at ON at.Id = aiv.ActorId
JOIN SubTitleTbl st ON st.Id = siv.STId