为什么控制台窗口不会水平而不是垂直打印数组内容？
有没有办法改变它？
如何使用Console.WriteLine()？
例如：
int[] numbers = new int[100]
for(int i; i < 100; i++)
{
numbers[i] = i;
}
for (int i; i < 100; i++)
{
Console.WriteLine(numbers[i]);
}
答案 0 :(得分：117)
您可能正在使用Console.WriteLine来打印数组。
int[] array = new int[] { 1, 2, 3 };
foreach(var item in array)
{
Console.WriteLine(item.ToString());
}
如果您不希望单独一行中的每个项目都使用Console.Write：
int[] array = new int[] { 1, 2, 3 };
foreach(var item in array)
{
Console.Write(item.ToString());
}
或string.Join<T>（在.NET Framework 4或更高版本中）：
int[] array = new int[] { 1, 2, 3 };
Console.WriteLine(string.Join(",", array));
答案 1 :(得分：27)
我建议：
foreach(var item in array)
Console.Write("{0}", item);
如上所述，除非一项是null，否则不会引发异常。
Console.Write(string.Join(" ", array));
string[] ，将是完美的
答案 2 :(得分：18)
只需循环遍历数组，然后使用Write代替WriteLine将项目写入控制台：
foreach(var item in array)
Console.Write(item.ToString() + " ");
只要您的商品没有任何换行符，就会生成一行。
...或者，正如Jon Skeet所说，为你的问题提供了更多的背景。
答案 3 :(得分：3)
foreach(var item in array)
Console.Write(item.ToString() + "\t");
答案 4 :(得分：2)
namespace ReverseString
{
class Program
{
static void Main(string[] args)
{
string stat = "This is an example of code" + "This code has written in C#\n\n";
Console.Write(stat);
char[] myArrayofChar = stat.ToCharArray();
Array.Reverse(myArrayofChar);
foreach (char myNewChar in myArrayofChar)
Console.Write(myNewChar); // Yuo just need to write the function Write instead of WriteLine
Console.ReadKey();
}
}
}
这是输出
#C ni nettirw sah edoc sihTedoc fo elpmaxe na si sihT
答案 5 :(得分：1)
如果你需要漂亮地打印一个像这样的数组，这可能会起作用 http://aaron-hoffman.blogspot.com/2013/11/pretty-print-array-of-arrays-in-net-c.html
public string PrettyPrintArrayOfArrays(int[][] arrayOfArrays)
{
if (arrayOfArrays == null)
return "";
var prettyArrays = new string[arrayOfArrays.Length];
for (int i = 0; i < arrayOfArrays.Length; i++)
{
prettyArrays[i] = "[" + String.Join(",", arrayOfArrays[i]) + "]";
}
return "[" + String.Join(",", prettyArrays) + "]";
}
示例输出：
[[2,3]]
[[2,3],[5,4,3]]
[[2,3],[5,4,3],[8,9]]
答案 6 :(得分：1)
int[] n=new int[5];
for (int i = 0; i < 5; i++)
{
n[i] = i + 100;
}
foreach (int j in n)
{
int i = j - 100;
Console.WriteLine("Element [{0}]={1}", i, j);
i++;
}
答案 7 :(得分：1)
public static void Main(string[] args)
{
int[] numbers = new int[10];
Console.Write("index ");
for (int i = 0; i < numbers.Length; i++)
{
numbers[i] = i;
Console.Write(numbers[i] + " ");
}
Console.WriteLine("");
Console.WriteLine("");
Console.Write("value ");
for (int i = 0; i < numbers.Length; i++)
{
numbers[i] = numbers.Length - i;
Console.Write(numbers[i] + " ");
}
Console.ReadKey();
}
}
}
答案 8 :(得分：0)
使用Console.Write仅在线程是写入控制台的唯一线程时才有效，否则您的输出可能会散布其他输出，这些输出可能会也可能不会插入换行符，以及其他不需要的字符。要确保完整打印数组，请使用Console.WriteLine编写一个字符串。大多数任何对象数组都可以使用.NET 4.0之前的非泛型连接水平打印（取决于类型的ToString（）方法）：
int[] numbers = new int[100];
for(int i= 0; i < 100; i++)
{
numbers[i] = i;
}
//For clarity
IEnumerable strings = numbers.Select<int, string>(j=>j.ToString());
string[] stringArray = strings.ToArray<string>();
string output = string.Join(", ", stringArray);
Console.WriteLine(output);
//OR
//For brevity
Console.WriteLine(string.Join(", ", numbers.Select<int, string>(j => j.ToString()).ToArray<string>()));
答案 9 :(得分：0)
下面的解决方案是最简单的
Console.WriteLine("[{0}]", string.Join(", ", array));
输出：[1, 2, 3, 4, 5]
另一个简短的解决方案
Array.ForEach(array, val => Console.Write("{0} ", val));
输出：1 2 3 4 5，或者如果您需要在下面添加添加,，请使用
int i = 0;
Array.ForEach(array, val => Console.Write(i == array.Length -1) ? "{0}" : "{0}, ", val));
输出：1, 2, 3, 4, 5
答案 10 :(得分：0)
我已经写了一些扩展名以适应几乎所有需求。
使用分隔符， String.Format 和 IFormatProvider 的扩展过载。
示例：
var array1 = new byte[] { 50, 51, 52, 53 };
var array2 = new double[] { 1.1111, 2.2222, 3.3333 };
var culture = CultureInfo.GetCultureInfo("ja-JP");
Console.WriteLine("Byte Array");
//Normal print
Console.WriteLine(array1.StringJoin());
//Format to hex values
Console.WriteLine(array1.StringJoin("-", "0x{0:X2}"));
//Comma separated
Console.WriteLine(array1.StringJoin(", "));
Console.WriteLine();
Console.WriteLine("Double Array");
//Normal print
Console.WriteLine(array2.StringJoin());
//Format to Japanese culture
Console.WriteLine(array2.StringJoin(culture));
//Format to three decimals
Console.WriteLine(array2.StringJoin(" ", "{0:F3}"));
//Format to Japanese culture and two decimals
Console.WriteLine(array2.StringJoin(" ", "{0:F2}", culture));
Console.WriteLine();
Console.ReadLine();
扩展名：
using System;
using System.Collections;
using System.Collections.Generic;
using System.Globalization;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace Extensions
{
/// <summary>
/// IEnumerable Utilities.
/// </summary>
public static partial class IEnumerableUtilities
{
/// <summary>
/// String.Join collection of items using custom Separator, String.Format and FormatProvider.
/// </summary>
public static string StringJoin<T>(this IEnumerable<T> Source)
{
return Source.StringJoin(" ", string.Empty, null);
}
/// <summary>
/// String.Join collection of items using custom Separator, String.Format and FormatProvider.
/// </summary>
public static string StrinJoin<T>(this IEnumerable<T> Source, string Separator)
{
return Source.StringJoin(Separator, string.Empty, null);
}
/// <summary>
/// String.Join collection of items using custom Separator, String.Format and FormatProvider.
/// </summary>
public static string StringJoin<T>(this IEnumerable<T> Source, string Separator, string StringFormat)
{
return Source.StringJoin(Separator, StringFormat, null);
}
/// <summary>
/// String.Join collection of items using custom Separator, String.Format and FormatProvider.
/// </summary>
public static string StringJoin<T>(this IEnumerable<T> Source, string Separator, IFormatProvider FormatProvider)
{
return Source.StringJoin(Separator, string.Empty, FormatProvider);
}
/// <summary>
/// String.Join collection of items using custom Separator, String.Format and FormatProvider.
/// </summary>
public static string StringJoin<T>(this IEnumerable<T> Source, IFormatProvider FormatProvider)
{
return Source.StringJoin(" ", string.Empty, FormatProvider);
}
/// <summary>
/// String.Join collection of items using custom Separator, String.Format and FormatProvider.
/// </summary>
public static string StringJoin<T>(this IEnumerable<T> Source, string Separator, string StringFormat, IFormatProvider FormatProvider)
{
//Validate Source
if (Source == null)
return string.Empty;
else if (Source.Count() == 0)
return string.Empty;
//Validate Separator
if (String.IsNullOrEmpty(Separator))
Separator = " ";
//Validate StringFormat
if (String.IsNullOrWhitespace(StringFormat))
StringFormat = "{0}";
//Validate FormatProvider
if (FormatProvider == null)
FormatProvider = CultureInfo.CurrentCulture;
//Convert items
var convertedItems = Source.Select(i => String.Format(FormatProvider, StringFormat, i));
//Return
return String.Join(Separator, convertedItems);
}
}
}
答案 11 :(得分：-3)
private int[,] MirrorH(int[,] matrix) //the method will return mirror horizintal of matrix
{
int[,] MirrorHorizintal = new int[4, 4];
for (int i = 0; i < 4; i++)
{
for (int j = 0; j < 4; j ++)
{
MirrorHorizintal[i, j] = matrix[i, 3 - j];
}
}
return MirrorHorizintal;
}