我的网页浏览功能不适用于重定向到其他网页的网址。它从应用程序打开浏览器,但不加载webview。有什么想法吗?
webview的代码是:
webView = (WebView) findViewById(R.id.simpleWebView);
WebSettings webSettings = webView.getSettings();
webSettings.setJavaScriptEnabled(true);
webView.setWebViewClient(new WebViewClient());
if(getIntent().getStringExtra("url")!=null){
loadLink(getIntent().getStringExtra("url"));
}else{
Toast.makeText(WebViewActivity.this, "Please try again later!",
Toast.LENGTH_SHORT).show();
finish();
}
答案 0 :(得分:4)
主类
public class Main extends Activity {
private WebView webview;
private static final String TAG = "Main";
private ProgressDialog progressBar;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
requestWindowFeature(Window.FEATURE_NO_TITLE);
setContentView(R.layout.main);
this.webview = (WebView)findViewById(R.id.webview);
WebSettings settings = webview.getSettings();
settings.setJavaScriptEnabled(true);
webview.setScrollBarStyle(WebView.SCROLLBARS_OUTSIDE_OVERLAY);
final AlertDialog alertDialog = new AlertDialog.Builder(this).create();
progressBar = ProgressDialog.show(Main.this, "WebView Example", "Loading...");
webview.setWebViewClient(new WebViewClient() {
public boolean shouldOverrideUrlLoading(WebView view, String url) {
Log.i(TAG, "Processing webview url click...");
view.loadUrl(url);
return true;
}
public void onPageFinished(WebView view, String url) {
Log.i(TAG, "Finished loading URL: " +url);
if (progressBar.isShowing()) {
progressBar.dismiss();
}
}
public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
Log.e(TAG, "Error: " + description);
Toast.makeText(activity, "Oh no! " + description, Toast.LENGTH_SHORT).show();
alertDialog.setTitle("Error");
alertDialog.setMessage(description);
alertDialog.setButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
return;
}
});
alertDialog.show();
}
});
webview.loadUrl("http://www.google.com");
}
}
您的main.xml布局
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
>
<WebView android:id="@string/webview"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:layout_weight="1" />
</LinearLayout>
答案 1 :(得分:1)
尝试覆盖Web视图客户端方法,这将有助于您
mWebView.setWebViewClient(new WebViewClient() {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
// Here put your code
Log.d("My Webview", url);
// return true; //Indicates WebView to NOT load the url;
return false; //Allow WebView to load url
}
});
答案 2 :(得分:0)
我认为你应该写下你的loadLink方法包含的内容。 你确定,你已经正确实现了它 - webView.loadUrl(...)?
答案 3 :(得分:0)
webView=(WebView)view.findViewById(R.id.webview);
webView.setWebViewClient(new MyBrowser());
webView.getSettings().setLoadsImagesAutomatically(true);
webView.getSettings().setJavaScriptEnabled(true);
webView.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY);
webView.loadUrl("https://www.google.co.in/");
return view;
}
private class MyBrowser extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
@Override
public void onPageFinished(WebView view, String url) {
pDialog.dismiss();
}
}
答案 4 :(得分:-2)
试试这个
if(getIntent().getStringExtra("url")!=null){
mWebView.loadUrl(getIntent().getStringExtra("url"));
}
并检查您是否获得了互联网许可