错误：未知标头类型：21

Question

我正在使用谷歌饼图我的json值为：

[
    ["Exhibitor Fee", 21], 
    ["Attendee Registration", 400], 
    ["Hotel Cost Per Night", 21212], 
    ["Sponsorship", 435], 
    ["Shippng", 456]
]

我的代码是：

var jsonValues = '<?php echo $staticEvent; ?>'
var pieValues = $.parseJSON(jsonValues);
console.log(pieValues);
google.charts.load('current', {'packages': ['corechart']});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {

    var data = google.visualization.arrayToDataTable(pieValues);

    var options = {
        title: 'My Daily Activities'

    };

    var chart = new google.visualization.PieChart(document.getElementById('piechart'));

    chart.draw(data, options);
}

Answer 1

通过事物here的外观，饼图期望第一个数组成为图表的标题，我想这应该是字符串，而你的第一个数组是string, int

尝试将您的json更改为：

[
    ["Activity", "Cost"],
    ["Exhibitor Fee", 21], 
    ["Attendee Registration", 400], 
    ["Hotel Cost Per Night", 21212], 
    ["Sponsorship", 435], 
    ["Shippng", 456]
]

Answer 2

你好吗，

试一试：

在你的php var $ staticEvent中;你改成：

<?php
     $staticEvent = json_encode($staticEvent, JSON_UNESCAPED_UNICODE);
?>

你的JS：

var jsonValues = '<?php echo $staticEvent; ?>';
var pieValues = $.parseJSON(jsonValues);
console.log(pieValues);
google.charts.load('current', {'packages': ['corechart']});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {

    var data = google.visualization.arrayToDataTable(pieValues);

    var options = {
        title: 'My Daily Activities'

    };

    var chart = new google.visualization.PieChart(document.getElementById('piechart'));

    chart.draw(data, options);
}