Question

使用基础实体中定义的常量数组填充Symfony表单choiceType的最佳方法是什么，并根据相同的常量添加创建断言。选项名称应存储在DB中。

我正在使用Symfony 2.8，这就是我所做的。它运作良好，但我认为必须有一个更简单的方法来使用所有新的表单功能。

谢谢，Hannes

实体

class User implements UserInterface, \Serializable
{
    const OCCUPATION_SCHOOL_HIGHER_DEGREE = 'Schülerin/Schüler an Gymnasium';
    const OCCUPATION_SCHOOL_LOWER_DEGREE = 'Schülerin/Schüler an Haupt-/Real- und anderen Schulen';
    const OCCUPATION_WORK_TRAINING = 'Berufsausbildung';
    const OCCUPATION_UNIVERSITY = 'Studium an einer Hochschule';
    const OCCUPATION_WORK_FULLTIME = 'Vollzeiterwerbstätigkeit';
    const OCCUPATION_WORK_PARTTIME = 'Teilzeiterwerbstätigkeit';
    const OCCUPATION_NATIONAL_SERVICE = 'Wehrdienst/Zivildienst/FSJ/FÖJ';
    const OCCUPATION_UNEMPLOYED = 'keine Beschäftigung';
    const OCCUPATION_OTHERS = 'sonstiges';

...
/**
     * @ORM\Column(type="string", length=255, nullable=true)
     * @Assert\NotBlank(message = "Pflichtfeld.")
     * @Assert\Choice(
     *      choices = {
     *          User::OCCUPATION_SCHOOL_HIGHER_DEGREE,
     *          User::OCCUPATION_SCHOOL_LOWER_DEGREE,
     *          User::OCCUPATION_WORK_TRAINING,
     *          User::OCCUPATION_UNIVERSITY,
     *          User::OCCUPATION_WORK_FULLTIME,
     *          User::OCCUPATION_WORK_PARTTIME,
     *          User::OCCUPATION_NATIONAL_SERVICE,
     *          User::OCCUPATION_UNEMPLOYED,
     *          User::OCCUPATION_OTHERS,
     *      },
     *      message = "Bitte wähle einen Eintrag aus der Liste."
     * )
     */
    private $occupation;

...
}

FormType

class UserRegisterType extends AbstractType
{
    /**
     * @param FormBuilderInterface $builder
     * @param array                $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        // Occupation
        $builder->add('occupation', ChoiceType::class, array(
                'label' => 'Beschäftigung*',
                'placeholder' => 'Bitte wählen',
                'choices' => array(
                    User::OCCUPATION_SCHOOL_HIGHER_DEGREE => User::OCCUPATION_SCHOOL_HIGHER_DEGREE,
                    User::OCCUPATION_SCHOOL_LOWER_DEGREE => User::OCCUPATION_SCHOOL_LOWER_DEGREE,
                    User::OCCUPATION_WORK_TRAINING => User::OCCUPATION_WORK_TRAINING,
                    User::OCCUPATION_UNIVERSITY => User::OCCUPATION_UNIVERSITY,
                    User::OCCUPATION_WORK_FULLTIME => User::OCCUPATION_WORK_FULLTIME,
                    User::OCCUPATION_WORK_PARTTIME => User::OCCUPATION_WORK_PARTTIME,
                    User::OCCUPATION_NATIONAL_SERVICE => User::OCCUPATION_NATIONAL_SERVICE,
                    User::OCCUPATION_UNEMPLOYED => User::OCCUPATION_UNEMPLOYED,
                    User::OCCUPATION_OTHERS => User::OCCUPATION_OTHERS,
                ),
                'choices_as_values' => true,
            )
        );

... }

Answer 1

不确定，如果这回答了你的问题，但是自从PHP 5.6（我希望这是正确的版本）你可以创建constancs作为数组：

const OCCUPATION = [
        User::OCCUPATION_SCHOOL_HIGHER_DEGREE,
        User::OCCUPATION_SCHOOL_LOWER_DEGREE,
        ....
    ];

或


    const OCCUPATION = [
            OCCUPATION_SCHOOL_HIGHER_DEGREE => 'Schülerin/Schüler an Gymnasium',
            OCCUPATION_WORK_TRAINING => 'Berufsausbildung',
            ....
        ];

现在你可以直接以你的形式访问：


     'choices' => User::OCCUPATION

或者你可以写一个getter $ user-＆gt; getOccupation（）;

Answer 2

几个月前我发现了这个bundle，我觉得它可以满足你的需要。

您可以在config.yml中存储可能的值（您可以使用类常量）。然后，您可以使用专用表单类型来检索您的选择，并在您的实体中添加验证约束。

使用常量数组

2 个答案: