使用php代码,如果我对id 2感兴趣,我想知道最新条目在哪一列。然后列' time4'随着时间的推移" 2016-03-01 10:01:01"是最新的条目。
id time1 time2 time3 time4
1 2016-01-01 09:27:24 2016-01-02 10:01:01 2016-01-02 17:05:07 2016-01-01 10:01:01
2 2016-01-02 09:27:24 2016-01-03 10:01:01 2016-02-02 17:05:07 2016-03-01 10:01:01
3 2016-01-02 10:27:24 2016-01-03 11:01:01 2016-02-02 18:05:07 2016-03-01 11:01:01
我试过这个
<?php
$User=1;
$result = $con->query("SELECT MAX(TimeToSelect) as Output
FROM (
SELECT time1 as TimeToSelect,id
FROM tableTime
union
SELECT time2,id
FROM tableTime
union
SELECT time3,id
FROM tableTime
union
SELECT time4,id
FROM tableTime
) as A
WHERE id = '$User'");
$row = $result->fetch_array(MYSQLI_BOTH);
echo $something=$row[0];
?>
然后它回应了约会日期&#34; 2016-03-01 10:01:01&#34;而不是列名&#34; time4&#34;。
答案 0 :(得分:0)
如果您只包含4个要比较的列,则可以使用以下SQL获取所需内容。
您可以更改在特定情况下输入最新时间的条件中的ID&#39; id&#39;。 (每次id)
SELECT MAX(TimeToSelect) as Output
FROM (
SELECT time1 as TimeToSelect,id
FROM tableTime
union
SELECT time2,id
FROM tableTime
union
SELECT time3,id
FROM tableTime
union
SELECT time4,id
FROM tableTime
) as A
WHERE id = 1
如果您想获取列名称,请尝试以下SQL:
SELECT ColumnName
FROM (
SELECT time1 AS TimeToSelect,id,'time1' AS ColumnName
FROM tableTime
UNION
SELECT time2,id,'time2'
FROM tableTime
UNION
SELECT time3,id,'time3'
FROM tableTime
UNION
SELECT time4,id,'time4'
FROM tableTime
) AS A
WHERE id = 1
AND TimeToSelect = (SELECT MAX(TimeToSelect)
FROM (
SELECT time1 AS TimeToSelect,id,'time1' AS ColumnName
FROM tableTime
UNION
SELECT time2,id,'time2'
FROM tableTime
UNION
SELECT time3,id,'time3'
FROM tableTime
UNION
SELECT time4,id,'time4'
FROM tableTime
) AS A
WHERE id = 1
)