Question

我有以下mongoose架构结构

userSchema = new Schema({
    roles: [
        role: {type: Schema.Types.ObjectId, ref: 'Role' }
    ]
})

rolesSchema = new Schema({
  name: String,
  roleEntities: [
    {
      entity : {type: Schema.Types.ObjectId, ref: 'RoleEntity' },
      abilities : [{type: Schema.Types.ObjectId, ref: 'Ability' }]
    }
  ]
}

roleEntitiesSchema = new Schema({
  name: String
})

abilitiesSchema = new Schema({
  name: String
})

如何在USER模型上执行查找时填充所有这些嵌套文档？

我尝试使用populate，如下所示

User.find(ctx.request.query).populate(
      {path: 'roles.role'
      ,populate: { path: 'roleEntities.entity'}
    }).
    exec()

但它没有解决roleEntities.entity

Answer 1

您可以尝试链接填充操作

User.find()
.populate("roles.role")
.populate("roles.role.roleEntities.entity")

Answer 2

猫鼬4：

User
  .find()
  .populate({
    path: 'roleIds',
    model: 'roles',
    populate: {
      path: 'otherIds',
      model: 'other'
    }
  })

Answer 3

对我来说，以下工作

  .populate({
            path: 'favorites.favorite',
            model: 'Joke',
            populate: {
              path: 'user',
              model: 'User',
            },

Answer 4

这是嵌套在多个对象/数组内部的深层人口的一个极端示例：

Deal.find()
    .populate({
      path: 'fund',
      populate: [{
        path: 'organizer',
        populate: {
          path: 'banking.accounts.transactions.associatedInvestment',
          model: 'Investment'
        }
      }, {
        path: 'documents'
      }]
    })

如何在mongoose中填充嵌套实体？

4 个答案: