Question

我已将图像上传到文件夹并将路径存储到MySQL数据库中。已存储路径，并且已成功将图像插入文件夹。但我的问题是当我从存储在db中的路径显示图像时。它没有显示。当我回显图像路径时，它显示图像路径。我检查了我的浏览器设置，一切都好。这是我的代码。请任何人帮忙。

$up=move_uploaded_file($_FILES['profile']['tmp_name'],dirname($_SERVER['DOCUMENT_ROOT']).'/htdocs/upload/image/'.$name);
$path = dirname($_SERVER['DOCUMENT_ROOT']).'/htdocs/upload/image/';
$location = $path . $_FILES['profile']['name'];
$ins=mysqli_query($con, "INSERT into image (url) values ('$location')");
echo 'image uploaded and stored';
echo "$location"; //It displays D:/xampp/htdocs/upload/image/Chrysanthemum.jpg
echo '<img width="250" height="250" src= "'.$location.'"/>';//It doesn't display anything.

Answer 1

试试这个：

尝试使用relative path而不是absolute path。相对路径可帮助您从任何服务器，任何目录运行脚本。

$path = 'upload/image/';
$location = $path . $_FILES['profile']['name'];

move_uploaded_file($_FILES['profile']['tmp_name'], $location);

$ins = mysqli_query($con, "INSERT into image (url) values ('$location')");
echo 'image uploaded and stored';
echo '<img width="250" height="250" src= "'.$location.'"/>';

注意：您需要具有相同的文件夹名称upload/image 脚本运行的目录。根据您的要求，您希望显示来自mysql的图像，但是没有这样做，因为您需要再次查询该表。

Answer 2

嘿，您可以使用下面的代码在dir中获取上传图片的路径，此代码将显示您的图片

$location ='/upload/image/'. $_FILES['profile']['name']; // write your project dir name before upload if "upload is not your project dir"

$ins=mysqli_query($con, "INSERT into image (url) values ('$location')");
echo 'image uploaded and stored';

echo '<img width="250" height="250" src= "'.$location.'"/>';//It doesn't display anything.

从mysql中存储的路径显示图像

2 个答案: