伙计我有两张不同的桌子。
表1:
contract-id | contract-date
1 | 01-05-2016
1 | 01-06-2016
1 | 01-07-2016
2 | 01-01-2016
2 | 01-02-2016
3 | 01-05-2016
3 | 01-06-2016
表2:
invoice-number|contract-id|invoice-from-date|invoice-to-date
1 |1 |01-05-2016 |31-05-2016
2 |1 |15-05-2016 |31-05-2016
3 |1 |25-05-2016 |31-05-2016
我的要求是,我必须显示当前月份来自表1的所有合同,我必须显示从表-2中为这些合同提出的发票数。如果有任何发票,它应显示其计数或只是零。预期的答案是:
contract-id|counts
1 |3
3 |0
合同ID:1的计数是3,因为我已经为当月提出了三张发票,而且合约ID:3的计数是0,因为我没有为它提出任何发票。而且合约ID:2缺失,因为它不属于当月。
这是我尝试过的:
select cbm_contract_period_value_split.contract_id,
count(cbm_contract_invoice_request.contract_id),
cbm_contract_period_value_split.contract_date
from cbm_contract_period_value_split
left outer join cbm_contract_invoice_request
on cbm_contract_period_value_split.contract_id = cbm_contract_invoice_request.contract_id
and MONTH(cbm_contract_period_value_split.contract_date) = MONTH(CURDATE())
and MONTH(cbm_contract_invoice_request.invoice_for_the_period_of_from_date) = MONTH(CURDATE())
我已经发布了这个问题,但是现在我发布了一个带有我得到的答案的编辑版本。然而,我没有得到理想的答案。怎么了,我该怎么办?
答案 0 :(得分:0)
试试这个。我认为你需要一个GROUP BY而我放入WHERE来过滤掉当前月份的行。
select pvs.contract_id,
count(ir.contract_id) as counts,
pvs.contract_date
from cbm_contract_period_value_split as pvs
left join cbm_contract_invoice_request as ir
on pvs.contract_id = ir.contract_id
and MONTH(ir.invoice_for_the_period_of_from_date) = MONTH(CURDATE())
WHERE MONTH(pvs.contract_date) = MONTH(CURDATE())
GROUP BY pvs.contract_id,pvs.contract_date
http://sqlfiddle.com/#!9/e5f08c/9
结果
contract_id counts contract_date
1 3 May, 01 2016 00:00:00
3 0 May, 01 2016 00:00:00
答案 1 :(得分:0)
SELECT Table-1.contract_id, Table-1.contract-date, COUNT(*) AS count FROM Table-2 LEFT JOIN Table-1 ON Table-1.contract_id = Table-2.contract_id WHERE MONTH(Table-1.contract-date) = MONTH(CURDATE()) GROUP BY Table-1.contract_id
答案 2 :(得分:0)