是否有更安全或标准的方式通过php访问您的mysql数据库然后明确写下您的凭据，如下所示......
$servername = "localhost";
$username = "user1";
$password = "pass1";
$dbname = "test-db";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
如果是这样，任何想法可以在哪里找到更多信息并研究这个主题？
答案 0 :(得分：2)
如果您在public ObservableCollection<MemoryItem> MemoryItems { get; set; } = new ObservableCollection<MemoryItem>();
public MainPageViewModel()
{
}
public string MemoryValue
{
get
{
return _memoryValue;
}
set
{
_memoryValue = value;
OnPropertyChanged("MemoryValue");
}
}
public static async Task Serializer()
{
var folder = ApplicationData.Current.RoamingFolder;
var file = await folder.CreateFileAsync("collection.json", CreationCollisionOption.ReplaceExisting);
using (var stream = await file.OpenStreamForWriteAsync())
using (var writer = new StreamWriter(stream, Encoding.UTF8))
{
string json = JsonConvert.SerializeObject(MemoryItems);
await writer.WriteAsync(json);
}
}
public static async Task Deserializer()
{
try
{
var folder = ApplicationData.Current.RoamingFolder;
var file = await folder.GetFileAsync("collection.json");
using (var stream = await file.OpenStreamForReadAsync())
using (var reader = new StreamReader(stream, Encoding.UTF8))
{
string json = await reader.ReadToEndAsync();
MemoryItems = JsonConvert.DeserializeObject<ObservableCollection<MemoryItem>>(json);
}
}
catch (Exception)
{
// Handle Exception.
}
}
堆栈上，请将其移至环境文件中，最好是public async void OnSuspending(object sender, SuspendingEventArgs args)
{
SuspendingDeferral deferral = args.SuspendingOperation.GetDeferral();
await MainPageViewModel.Serializer();
deferral.Complete();
}
public override async Task OnStartAsync(StartKind startKind, IActivatedEventArgs args)
{
NavigationService.Navigate(typeof(Views.MainPage));
await MainPageViewModel.Deserializer();
await Task.CompletedTask;
}
环境文件。
apache然后你就可以在PHP中访问它了。
LAMP