Question

我是Django的新手。我有客户端应用程序，它将POST请求发送到服务器以在服务器上创建新的Conference对象。 Serverside代码如下所示：

new_conf.date = request.POST['date']
new_conf.name = request.POST['name']
new_conf.languages = request.POST['languages']
new_conf.is_open = request.POST['is_open']
new_conf.place = request.POST['place']
new_conf.recognition_on = request.POST['recognition_on']

有没有办法把它写得更短？是否可以编写一些通用模板以在类似情况下使用？

Answer 1

您可以在模型中创建ModelForm表单，并将请求“解压缩”。将数据存入模型实例

# Create a form instance from POST data.
>>> conf_form = ConferenceForm(request.POST)

# Save a new Conference object from the form's data.
>>> new_conf = conf_form.save()

REF。 https://docs.djangoproject.com/es/1.9/topics/forms/modelforms/#the-save-method

或者，对于更多Python通用解决方案，您可以列出所需的密钥并使用setattr或设置dict中的密钥，如下所示

for key in ['date', 'name', 'languages', ...]:
    setattr(new_conf, key, request.POST[key])

    # Or if new_conf is a dict-like obj
    new_conf[key] = request.POST[key]

用于在Django中提取POST值的模板

1 个答案: