这是一个简单的POC:
public void main(String[] args) {
final String FILE_NAME = "c:/poc.ser";
try {
HotelJdo hotel = HotelJdoFinder.findById(430);
ObjectOutputStream oos = new ObjectOutputStream(new FileOutputStream(FILE_NAME));
// serialize the object
oos.writeObject(hotel);
oos.close();
// read the object in the same vm
ObjectInputStream ois = new ObjectInputStream(new FileInputStream(FILE_NAME));
HotelJdo hotel2 = (HotelJdo) ois.readObject();
// this line throws an exception
System.out.println("number of crs channels: " + hotel2.getAvailableRooms().size());
ois.close();
} catch (Exception e) {
System.out.println("Unexpected exception:");
e.printStackTrace();
}
}
hotel2.getAvailableRooms()查询配置为使用透明间接的房间列表。并且该调用抛出以下异常:
Exception [EclipseLink-7242] (Eclipse Persistence Services - 1.2.1.v20100428-r70
82): org.eclipse.persistence.exceptions.ValidationException
Exception Description: An attempt was made to traverse a relationship using indi
rection that had a null Session. This often occurs when an entity with an unins
tantiated LAZY relationship is serialized and that lazy relationship is traverse
d after serialization. To avoid this issue, instantiate the LAZY relationship p
rior to serialization.
at org.eclipse.persistence.exceptions.ValidationException.instantiatingV
alueholderWithNullSession(ValidationException.java:975)
at org.eclipse.persistence.internal.indirection.QueryBasedValueHolder.in
stantiate(QueryBasedValueHolder.java:83)
at org.eclipse.persistence.internal.indirection.QueryBasedValueHolder.in
stantiate(QueryBasedValueHolder.java:75)
at org.eclipse.persistence.internal.indirection.DatabaseValueHolder.getV
alue(DatabaseValueHolder.java:83)
at org.eclipse.persistence.indirection.IndirectList.buildDelegate(Indire
ctList.java:237)
at org.eclipse.persistence.indirection.IndirectList.getDelegate(Indirect
List.java:397)
at org.eclipse.persistence.indirection.IndirectList.size(IndirectList.ja
va:726)
我知道我可以在序列化之前触发房间列表的初始化,但我想知道如何将hotel2对象重新附加到EclipseLink会话以便懒惰地获取房间列表。
答案 0 :(得分:2)
要重新附加对象,您必须先使用EntityManager.merge
方法才能访问其关系。
类似的东西:
hotel2 = em.merge(hotel2);