Question

我已经编写了一个脚本来从API获取数据并返回它，但现在我需要解析该数据，这是json数据的样子的一个示例，我正在寻找一些字典值拉。

{'results': [{'icpsr_id': 21133,
   'twitter_id': 'RepToddYoung',
   'thomas_id': '02019',
   'term_end': '2017-01-03',
   'office': '1007 Longworth House Office Building',
   'gender': 'M',
   'phone': '202-225-5315',

这是我编写的代码，用于解析json数据文件。谁能告诉我它有什么问题？我仍然从'结果'字典中返回完整的值，这意味着它就像代码没有做任何事情，我仍然得到完整的字典，它没有被解析而不是 ONLY 'twitter_id'和'office'

import requests
import json

def call():
    payload = {'apikey':'my_apikey', 'zip':'74120'}
    bas_url = 'http://openstates.org/api/v1//legislators/?state=ok'
    r = requests.get(bas_url, params = payload)
    grab = r.json()
    return grab
    jsonResponse=json.loads(decoded_response)
    jsonData = jsonResponse["results"]
    for item in jsonData:
        chamber = item.get("twitter_id")
        last_name = item.get("office")

Answer 1

听起来你想要这样的东西：

def call():
    payload = {'apikey':'my_apikey', 'zip':'74120'}
    bas_url = 'http://openstates.org/api/v1//legislators/?state=ok'
    r = requests.get(bas_url, params = payload)
    grab = r.json()
    jsonData = grab["results"]
    return [{key: value for key, value in result.items() if key in ("twitter_id", "office")} for result in jsonData]

Answer 2

好的，查看请求模块的在线文档，我看到调用r.json()将为您执行JSON解析，并返回一个Python dict。您发布的内容是该dict的输出，因此JSON部分已经为您处理。

使用json_response = r.json()将数据提取到json_response后，此代码应该在Python 2和Python 3中都有效：

extracted_values = []
json_data = json_response['results']
for item in json_data:
    subitem_dict = {}
    for key in 'twitter_id office'.split():
        subitem_dict[key] = item.get(key) # will give None if key does not exist
    extracted_values.append(subitem_dict)

print(extracted_values)

打印：

[{'twitter_id': 'RepToddYoung', 'office': '1007 Longworth House Office Building'}, 
 {'twitter_id': 'SenDonnelly', 'office': '720 Hart Senate Office Building'}, 
 {'twitter_id': 'SenDanCoats', 'office': '493 Russell Senate Office Building'}]

用python解码json字典

2 个答案: