Question

我有这段代码：

 def negate_sequence(text):
        negation = False
        delims = "?.,!:;"
        result = []
        words = text.split()
        prev = None
        pprev = None
        for word in words:
            stripped = word.strip(delims).lower()
            negated = "not " + stripped if negation else stripped
            result.append(negated)
            if any(neg in word for neg in ["not", "n't", "no"]):
                negation = not negation

            if any(c in word for c in delims):
                negation = False

        return result

    text = "i am not here right now, because i am not good to see that"
    sa = negate_sequence(text)
    print(sa)

这个代码做了什么，基本上他在下一个单词中添加'not'，并且他不会停止添加'not'直到他得到其中一个“？。，！：;”例如，如果您运行此代码，它们就像某种中断。

['i', 'am', 'not', 'not here', 'not right', 'not now', 'because', 'i', 'am', 'not', 'not good', 'not to', 'not see', 'not that']

我想要做的是添加空间而不是所有这些“？。，！：;”所以，如果我必须运行代码，我将得到这个结果：

['i', 'am', 'not', 'not here', 'right', 'now', 'because', 'i', 'am', 'not', 'not good', 'to', 'see', 'that']

所以代码只将'not'添加到下一个单词并在找到空格后中断，但我已经尝试了一切，但没有任何对我有用，如果有人知道如何做到这一点，我将不胜感激。。。提前谢谢。

Answer 1

我不完全确定你要做什么，但似乎你想把每一个否定都变成双重否定？

def is_negative(word):
    if word in ["not", "no"] or word.endswith("n't"):
        return True
    else:
        return False

def negate_sequence(text):
    text = text.split()
    # remove punctuation
    text = [word.strip("?.,!:;") for word in text]
    # Prepend 'not' to each word if the preceeding word contains a negation.
    text = ['not '+word if is_negative(text[i]) else word for i, word in enumerate(text[1:])]
    return text

print negate_sequence("i am not here right now, because i am not good to see that")

Answer 2

ipsnicerous的优秀代码完全符合您的要求，除了它错过了第一个单词。这可以通过使用is_negative（text [i-1]和更改枚举（text [1：]枚举（text [：]给你：

）轻松纠正

def is_negative(word):
    if word in ["not", "no"] or word.endswith("n't"):
        return True
    else:
        return False

def negate_sequence(text):
    text = text.split()
    # remove punctuation
    text = [word.strip("?.,!:;") for word in text]
    # Prepend 'not' to each word if the preceeding word contains a negation.
    text = ['not '+word if is_negative(text[i-1]) else word for i, word in enumerate(text[:])]
    return text

if __name__ =="__main__":
    print(negate_sequence("i am not here right now, because i am not good to see that"))

如何在条件Python中添加空间

2 个答案: