为了与api结合构建分页,当我按 next 按钮时,我希望将值next
分配给javascript变量,以便将其发送到PHP脚本。到目前为止我有这个,但我对Javascript不是很熟悉:
nextpage = document.getElementById('nextpage').onclick = document.getElementById('nextpage').value;
if(!nextpage==0){
link =link+"&nextpage="+nextpage;
}
这样Javascript变量就会被发布到url中,所以另一方面PHP脚本可以像这样选择它。对于我使用的其他变量:
mantinee = document.zoekform.mantinee.value;
if(!mantinee==0){
link =link+"&mantinee="+mantinee;
}
如果我这样做,那么它会直接发布到url,所以PHP脚本总是认为它需要跳到下一页,这不是我的意图。单击按钮会在单击时调用ajaxgetinfo()
。
query.php
if(isset($_POST['nextpage']))
{
$nextpage = $_POST['nextpage'];
}
以下是获取每个变量并传递它们的所有javascript。这是下一页也需要运行的地方
function vorige(){
sort = 'vorige';
ajaxGetInfo(sort);
}
函数ajaxGetInfo(排序) { var ajaxRequest; // De变量wat Ajax mogelijk maakt
try{
// Chrome, Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
link="query.php?";
datumreeks='';
if(document.zoekform.zo.checked==true){datumreeks="zondag";}
if(document.zoekform.ma.checked==true){datumreeks=datumreeks+"maandag-";}
if(document.zoekform.di.checked==true){datumreeks=datumreeks+"dinsdag-";}
if(document.zoekform.wo.checked==true){datumreeks=datumreeks+"woensdag-";}
if(document.zoekform.don.checked==true){datumreeks=datumreeks+"donderdag-";}
if(document.zoekform.vr.checked==true){datumreeks=datumreeks+"vrijdag-";}
if(document.zoekform.za.checked==true){datumreeks=datumreeks+"zaterdag-";}
link = link+"&datumreeks="+datumreeks;
datepicker = document.zoekform.datepicker.value;
if(!datepicker==0){link =link+"&datepicker="+datepicker;}
datepicker2 = document.zoekform.datepicker2.value;
if(!datepicker2==0){link =link+"&datepicker2="+datepicker2;}
zaal = document.zoekform.zaal.value;
if(!zaal==0){link =link+"&zaal="+zaal;}
genre = document.zoekform.genre.value;
if(!genre==0){link =link+"&genre="+genre;}
profiel = document.zoekform.profiel.value;
if(!profiel==0){link =link+"&profiel="+profiel;}
internationaal = document.zoekform.internationaal.value;
if(!internationaal==0){link =link+"&internationaal="+internationaal;}
prijslaag = document.zoekform.prijslaag.value;
if(!prijslaag==0){link =link+"&prijslaag="+prijslaag;}
prijshoog = document.zoekform.prijshoog.value;
if(!prijshoog==0){link =link+"&prijshoog="+prijshoog;}
mantinee = document.zoekform.mantinee.value;
if(!mantinee==0){link =link+"&mantinee="+mantinee;}
document.getElementById('nextpage').onclick = function(e){
ajaxRequest.open("POST", link, true);
if (nextpage) ajaxRequest.send("nextpage=yes");
}
ajaxRequest.open("GET", link, true);
ajaxRequest.send(null);
document.getElementById("info").innerHTML = '<div align=center><i class="material-icons w3-spin w3-jumbo">refresh</i></br>Blijft dit staan? <a href="" onclick="ajaxGetInfo()">Klik hier.</a></div>';
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
document.getElementById("info").innerHTML = ajaxRequest.responseText;
}
}
}
我怎样才能使Javascript变量(nextpage
)保持为空,直到按下按钮(name="nextpage"
并带有value="nextpage"
)?按下时,javascript变量nextpage
应包含“nextpage”
答案 0 :(得分:2)
发布您的变量而不是使用GET:
document.getElementById('nextpage').onclick = function(e){
ajaxRequest.open("POST", link, true);
if (nextpage) ajaxRequest.send("nextpage=yes");
document.getElementById("info").innerHTML = '<div align=center><i class="material-icons w3-spin w3-jumbo">refresh</i></br>Blijft dit staan? <a href="" onclick="ajaxGetInfo()">Klik hier.</a></div>';
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
document.getElementById("info").innerHTML = ajaxRequest.responseText;
}
}
}
答案 1 :(得分:0)
如果我的问题正确,你的问题是nextpage = [...]
。
以这种方式尝试:
document.getElementById('nextpage').onclick = function(e){
//do your request etc
}