对于下面的MySQL表,PHP函数只会测试'subcheck'是否等于1?
提前致谢,
约翰
`submission` (
`submissionid` int(11) unsigned NOT NULL auto_increment,
`loginid` int(11) NOT NULL,
`title` varchar(1000) NOT NULL,
`slug` varchar(1000) NOT NULL,
`url` varchar(1000) NOT NULL,
`displayurl` varchar(1000) NOT NULL,
`datesubmitted` timestamp NOT NULL default CURRENT_TIMESTAMP,
`subcheck` tinyint(1) NOT NULL,
PRIMARY KEY (`submissionid`)
)
答案 0 :(得分:0)
您没有提供所需的信息,例如表名,检查条件,所以我只是给您一个简单的查询供您使用...
$query = mysql_query('SELECT subcheck FROM your_table WHERE subcheck = "1"');
if ($query)
{
//your subcheck is 1
}
else
{
//your subcheck is not 1 / nothing was found
}
如果您只需要选择具有特定提交内容的提交者,则最好将其更改为以下内容:
$submissionid = 809;
$query = mysql_query('SELECT subcheck
FROM your_table
WHERE submissionid = "' . $submissionid . '"');
if ($row = mysql_fetch_row($query))
{
if ($row[0] == 1) { } //your subcheck is one
else { } //your subcheck is not one
}
else { } //no matching records found
如果它来自一个不安全的来源,例如用户输入,请记住转义$ submissionid!