我希望标签可点击以在safari中打开网址, 点击
时,电子邮件中的电话号码和电子邮件地址override func viewDidLoad() {
super.viewDidLoad()
// DetailsSV.contentSize.height=1120
print("idis \(self.strUserid)")
let ref = Firebase(url: "https://businesswallet.firebaseio.com/Users")
ref.childByAppendingPath(self.strUserid as String).observeEventType(.Value, withBlock: { snapshot in
if let dict = snapshot.value as? NSMutableDictionary{
print("dict is \(dict)")
if let Email = dict["Email"] as? String {
self.EmailL.text = Email
}
if let name = dict["BusinessName"] as? String {
self.BusinessNameL.text = name
self.navigationItem.title = name
}
if let ShortDescription = dict["ShortDescription"] as? String {
self.ShortDescriptionL.text = ShortDescription
}
if let City = dict["City"] as? String {
self.CityL.text = City
}
if let ContactMe = dict["ContactMe"] as? String {
self.ContactMeL.text = ContactMe
}
if let PhoneNumber = dict["PhoneNumber"] as? String {
self.PhoneNumberL.text = PhoneNumber
}
if let Website1 = dict["Website1"] as? String {
self.Website1L.text = Website1
}
if let Website2 = dict["Website2"] as? String {
self.Website2L.text = Website2
}
if let Category = dict["Category"] as? String {
self.CategoryL.text = Category
}
if let Details = dict["Details"] as? String {
self.DetailsTV.text = Details
}
}
})
我添加了这个功能,但它不起作用:
if let Website1 = dict["Website1"] as? String {
self.Website1L.text = Website1
let weblurl = NSURL(string: "open page:\(Website1)")
UIApplication.sharedApplication().openURL(weblurl!)
}
答案 0 :(得分:0)
尝试使用UITextView。如果您不希望用户能够编辑UITextView内的文本,您可以取消选中" Editable"在UITextView的属性检查器中。如果您希望UITextView能够检测链接,电话号码,事件和地址等文本字符串,您可以在UITextView的属性检查器中检查适用的文本。
如果您知道只有一个链接要显示,只需添加一个包含所需文本的按钮,然后将其发送给Safari。