Jackson - 将class1的json表示的Object类型字段映射到class2

时间:2016-05-02 11:08:00

标签: java json jackson gson

我定义了两个POJO:

Class1 -

public class Class1 {

        Map<String, Object> param1 = new HashMap<String, Object>();
        Map<String, Object> param2 = new HashMap<String, Object>();
        Object body;

        // getters-setters...
}

Class2 -

public class Class2   {

  private String name = null;
  private String description = null;
  private List<Integer> data = new ArrayList<Integer>();

  // getters-setters...
  }

body字段是动态的,所以我把它变成了Object类型。我使用swagger codegen在运行时生成Class2 Pojo。所以基本上body对象代表Class2。 Class1是固定类,字段是已知的。

json -
{
  "param1" : {
    "id" : 132
  },
  "param2" : {
    "address" : "String"
  },

  "body" : {
    "name" : "value",
    "description" : "value",
    "data" : [ ]
  }
}

我可以在Json上面反序列化Class1:

ObjectMapper mapper = new ObjectMapper();
Class1 ij = mapper.readValue(new File(path_of_above_json), Class1.class);
param1 = ij.getParam1();
param2 = ij.getParam2();
Object body = ij.getBody();

我想将body字段映射到Class2。我可以用gson做同样的事情:

Class2 body1 = new Class2();
Gson gson = new GsonBuilder().registerTypeAdapter(Class2.class, new ResponseBodyDeserializer<Class2>()).create();
ObjectMapper mapper = new ObjectMapper();
InputStream in = MainClass.class.getResourceAsStream(path_of_above_json);
BufferedReader r = new BufferedReader(new InputStreamReader(in));
body1 = gson.fromJson(r , Class2.class);

附加类ResponseBodyDeserializer -

class ResponseBodyDeserializer<T> implements JsonDeserializer<T>
{
    @Override
    public T deserialize(JsonElement je, Type type, JsonDeserializationContext jdc)
        throws JsonParseException
    {
        // Get the element from the parsed JSON
        JsonElement content = je.getAsJsonObject().get("body");

        // Deserialize it
        return new Gson().fromJson(content, type);
    }
}

我们能否与杰克逊达成同样的目的,以避免这一额外的课程?

谢谢!

2 个答案:

答案 0 :(得分:1)

以下是代码的修改版本

    public class Class1<T> {

            Map<String, Object> param1 = new HashMap<String, Object>();
            Map<String, Object> param2 = new HashMap<String, Object>();
            T body;

            // getters-setters...
    }

    ObjectMapper mapper = new ObjectMapper();
    Class1 ij = mapper.readValue(new File(path_of_above_json), Class1<Class2>.class);
    param1 = ij.getParam1();
    param2 = ij.getParam2();

Class2 body1 = ij.getBody();

答案 1 :(得分:1)

public static class Class1<T> {
    private Map<String, Object> param1 = new HashMap<String, Object>();
    private Map<String, Object> param2 = new HashMap<String, Object>();
    private T body;
}

并像这样使用它:

ObjectMapper mapper = new ObjectMapper();
Class1<Class2> ij =  mapper.readValue(json, new TypeReference<Class1<Class2>>() {});
Map<String, Object> param1 = ij.getParam1();
Map<String, Object> param2 = ij.getParam2();
Class2 body = ij.getBody();