Question

继续我的问题。

我想在where子句上显示agregate函数。但是发生了错误。

我的桌子：

我试过这样的方法（哪种方法是在where子句后显示sales_id的总购买量。

select * from customer where customer_id = ANY (
    select customer_id from sales where sales_id = ANY (
        select sales_id from sales_detail where sum(total) < (
            select sum(total) from sales_detail where sales_id = (
                select sales_id from sales where customer_id = (
                    select customer_id from customer where name = 'steven'
                    ) 
                )
            ) group by sales_id
        )
    )

我试过这样的（购买次数在子查询中）

select * from customer where customer_id = ANY (
    select customer_id from sales where sales_id = ANY (
        select sales_id from sales_detail where (
            select sum(total) from sales_detail where sales_id = (
                select sales_id from sales where customer_id = (
                    select customer_id from customer where name = 'steven'
                    )
                )
            )
            < ANY (
            select sum(total) as number_of_purchase, sales_id /*, sales_id*/ from sales_detail group by sales_id
            ) group by sales_id
        )
    )

我已经显示了这5个销售ID的购买数量

select sum(total) as number_of_purchase, sales_id /*, sales_id*/  
from sales_detail 
group by sales_id

，结果就像这样

我想要的是

我想要显示＆＃39; costumer name＆＃39;和＆＃39; costumer id＆＃39;其中购买次数为＆＃39;超过购买数量＆＃39; ＆＃39;史蒂文＆＃39;

史蒂文的购买数量为3

所以结果应该是这样的

| name | customer_id|
| Clark | c03 |
| Josh | c05 |

因为所有购买总数超过3 您可以从上面的结果中查看

THX。

Answer 1

select customer_id , name ,sum(total)
from customer ,sales_detail d, Sales s 
where d.sales_id = s.sales_id
and  customer_id = s.customer_id
having sum(total) > ( select sum(total)
                      from customer , sales s, sales_detail d
                      where customer_id = s.customer_id
                      and d.sales_id = s.sales_id 
                      and name = 'Steven')

Answer 2

大家好。根据你的建议，我明白了。

我只是重新创建查询并变成这样。：d

select * from customer where customer_id = ANY (
    select customer_id from sales where sales_id = ANY (
        select sales_id from sales_detail
            group by sales_id
            having sum(sales_detail.total) > (
                select sum(total) from sales_detail where sales_id = (
                    select sales_id from sales where customer_id = (
                        select customer_id from customer where name = 'steven'
                        )
                    )
                )
        )
    )

如何在where子句上显示agregate？或者有没有其他方法来解决这个问题

2 个答案: