Question

我已为列表项设置了全局模型，如下所示

在控制器初始化方法

中

var data = {
        A1: [
            {"id":"1","Type":"Incidents","Ticket":"P1-P2","value":90 },
            {"id":"2","Type":"Incidents","Ticket":"P1-P2","value":93  },
            {"id":"3","Type":"Resolution Time PM","Ticket":"P1-P2","value":96 },
            {"id":"4","Type":"Resolution Time BS","Ticket":"P1-P2","value":70  },
            {"id":"5","Type":"Resolution Time SCI","Ticket":"P1-P2","value":83 },
            {"id":"6","Type":"Incidents","Ticket":"P1-P2","value":90 },
            {"id":"7","Type":"Incidents","Ticket":"P1-P2","value":93  },
            {"id":"8","Type":"Resolution Time PM","Ticket":"P1-P2","value":96 },
            {"id":"9","Type":"Resolution Time BS","Ticket":"P1-P2","value":70  },
            {"id":"10","Type":"Resolution Time SCI","Ticket":"P1-P2","value":83 },
            {"id":"11","Type":"Incidents","Ticket":"P1-P2","value":90 },
            {"id":"12","Type":"Incidents","Ticket":"P1-P2","value":93  }]
    var oModel = new sap.ui.model.json.JSONModel();  
    oModel.setData(data);  
    sap.ui.getCore().setModel(oModel,'model_tickets');
    this.List_tickets.setModel(oModel);
    this.List_tickets.bindAggregation("items","/A1",this.List_ticketsTemplate);

在视图中创建内容

    oController.List_tickets = new sap.m.List("List_tickets",{}),
        oController.List_ticketsTemplate = new sap.m.ObjectListItem("tickets",{
        title : "{Type}",
        number: "{value}"
         press : oController.NavtoTicketDetails,
        attributes : [new sap.m.ObjectAttribute({
        text : "{Ticket}",
            })],

Listitem的

onpress事件应用导航到对象标题页，其中显示列表项的更多详细信息，其中列表的id作为属性在其他页面中的路由中传递

如何过滤所选id的全局模型并分配给对象头，基本上将对象头与所选列表项值绑定。

Answer 1

你说你可以获得身份证明。然后，您应该将对象标题页绑定到所选项。（如果您愿意，也可以专门绑定列表。）

this.getView().bindElement("model_tickets>/A1/" + id);

也不是说绑定的语法应该以命名的模型名称作为前缀：

...
        title : "{model_tickets>Type}",
        number: "{model_tickets>value}"
...
        text : "{model_tickets>Ticket}",

希望这有帮助

sap ui5对象头绑定

1 个答案: