Scala解决方案适用于连续产品

Question

我使用scala解决了一个问题，我的解决方案是：

object ConsecutiveProduct extends App {

 def getConsecutiveProduct(group: Int, number: String): Int = {
   val result = number.sliding(group).map(product)

  result.max
 }

 def product(number: String): Int = number.map(_.asDigit).product

 val str = """73167176531330624919225119674426574742355349194934
          |96983520312774506326239578318016984801869478851843
          |85861560789112949495459501737958331952853208805511
          |12540698747158523863050715693290963295227443043557
          |66896648950445244523161731856403098711121722383113
          |62229893423380308135336276614282806444486645238749
          |30358907296290491560440772390713810515859307960866
          |70172427121883998797908792274921901699720888093776
          |65727333001053367881220235421809751254540594752243
          |52584907711670556013604839586446706324415722155397
          |53697817977846174064955149290862569321978468622482
          |83972241375657056057490261407972968652414535100474
          |82166370484403199890008895243450658541227588666881
          |16427171479924442928230863465674813919123162824586
          |17866458359124566529476545682848912883142607690042
          |24219022671055626321111109370544217506941658960408
          |07198403850962455444362981230987879927244284909188
          |84580156166097919133875499200524063689912560717606
          |05886116467109405077541002256983155200055935729725
          |71636269561882670428252483600823257530420752963450""".filter(_.isDigit)
      println(getConsecutiveProduct(5, str))
 }    

所以根据问题，必须计算最高的相邻数字产品，对于具有最高产品的5个相邻数字的输入，我得到的结果正确为40824，但是根据我在这里传递13时的问题{{1即连续13位数的最高乘积我得到的结果为＆＃39; 2091059712＆＃39;，但它不是正确的答案，因为我试图在相应的网站输入，我尝试调试但无法找到我做错了，请有人帮忙。

Answer 1

所需产品超过32位整数，因此会溢出。请改用Long。这包括asDigit的结果，即：

number.map(_.asDigit.toLong).product