Question

有没有办法在if语句中使用原始输入？我想问用户一个问题，如果他们输入“是”，我想编码继续在if语句之后工作。如果他们输入“否”，我希望代码说“谢谢您的时间”，然后停止该特定if语句后的所有操作。这可能吗？

代码（我之前从未这样做，所以这是一个疯狂的猜测）：

    tri=raw_input("Do the points that you entered form a triangle? (yes or no)")  
    tri=str(tri)  

if tri == "yes" or "Yes" or "YES":   
    print "Your triangle is an:"  
elif tri == "no" or "NO" or "No":  
    print "Thank you for your time."  
else:  
    print "Not a valid answer, please try again later."

Answer 1

试一试：

import numpy as np
import matplotlib.pyplot as plt

t = 0.0
y = 0.0
u = 0.0
F = 1.073
Wd = 2*np.pi
w0 = 1.5*Wd
b = w0/4

ts =[]
ys =[]

h= 0.001

while (t <= 30):
    m1 = u
    k1 = (-w0**2)*np.sin(y) + u*(-2*b) + F*(w0**2)*np.cos(Wd*t)
    m2 = u + (h / 2.) * k1
    t_2 = t + (h / 2.)
    y_2 = y +(h / 2.) * m1
    u_2 = m2
    k2 = (-w0**2)*np.sin(y_2) + u_2*(-2*b) + F*(w0**2)*np.cos(Wd*t_2)
    m3 = u + (h / 2.) * k2
    t_3 = t + (h / 2.)
    y_3 = y + (h / 2.) * m2
    u_3 = m3
    k3 = (-w0**2)*np.sin(y_3) + u_3*(-2*b) + F*(w0**2)*np.cos(Wd*t_3)
    m4 = u + h * k3
    t_4 = t + h
    y_4 = y + h * m3
    u_4 = m4
    k4 = (-w0**2)*np.sin(y_4) + u_4*(-2*b) + F*(w0**2)*np.cos(Wd*t_4)
    t = t + h
    y = y + (h / 6.) * (m1 + (2 * m2) + (2 * m3) + m4)
    u = u + (h / 6.) * (k1 + (2 * k2) + (2 * k3) + k4)
    ts.append(t)
    ys.append(y)

plt.plot(ts,ys)
plt.xlabel('$t$',fontsize=18)
plt.ylabel('$\phi$',fontsize=18)
plt.axhline(y=0, color = 'black')
plt.show()

If语句中的原始输入？

1 个答案: