Question

我有点鼠标监听器，但我不知道如何将它们绑在一起。当用户点击播放游戏按钮时，我试图激活一个tic tac toe游戏。非常感谢协助。

    import java.awt.*;
    import java.awt.BorderLayout;
    import java.awt.FlowLayout;
    import java.awt.EventQueue;
    import javax.swing.UIManager;
    import javax.swing.UnsupportedLookAndFeelException;
    import java.awt.GridBagLayout;
    import java.awt.event.*;
    import java.awt.event.ActionListener.*;
    import javax.swing.*;
    import javax.swing.JFrame;
    import javax.swing.JPanel;
    import javax.swing.JLabel;
    import javax.swing.JButton;
    import javax.swing.ImageIcon;
    import javax.swing.border.EmptyBorder;
    import javax.swing.JOptionPane;
    import java.awt.Color;

    public class Use_PF_Interface extends JFrame implements Pet_Fish_Interface, MouseListener
     {
        // instance variables - replace the example below with your own
        private JFrame window;
        private JPanel backgroundPanel;
        private JLabel lblBackgroundImage = new JLabel();
        private JButton feedButton = new JButton("Feed Fish");
        private JButton playGamesButton = new JButton("Play Game");
        volatile private boolean mouseDown = false;

        //creates frame window
        public Use_PF_Interface()
        {
           setTitle("Virtual Pet Fish");
           setSize(400, 400);

           //initializes panels and panel layout
           backgroundPanel = new JPanel(); 
           backgroundPanel.setOpaque(false); 
           backgroundPanel.setLayout(new FlowLayout());

           lblBackgroundImage.setLayout(new FlowLayout());

           //sets background image of panel
           lblBackgroundImage.setIcon(new ImageIcon("OCEAN2.jpg"));
           lblBackgroundImage.setLayout(new BorderLayout()); 
           lblBackgroundImage.setBounds(0, 0, 400, 400);


            //adds button to panels
            backgroundPanel.add(feedButton);
            backgroundPanel.add(playGamesButton);
            lblBackgroundImage.add(backgroundPanel);


            add(lblBackgroundImage);


            feedButton.addMouseListener(this);
            playGamesButton.addMouseListener(listener);

            addMouseListener(this);


            }//creates frame window

         /**
         * This method will create an action for the button.
         * @pre none
         * @return tic tac toe game
         * @param none
         * @post none
         */

         public void mousePressed(MouseEvent e)
         {

             if (e.getButton() ==  MouseEvent.playGamesButton)
             {
               mouseDown = true;
               Tic_Tac_Toe();
              }
        }

        public void mouseReleased(MouseEvent e)
        {
             if(e.getButton() == MouseEvent.feedButton)
             {
                mouseDown = false;

             }
         }

          public void mouseExited(MouseEvent e)
          {
          }

我目前收到此错误：Use_PF_interface不是抽象的，并且不会覆盖java.awt.event.MouseListener中的抽象方法mouseEntered（java.awt.event.MouseEvent）

Answer 1

解决方案非常简单。 MouseListener是一个接口。接口是一个带有方法的类，实现此接口的类必须包含这些方法。即使这些方法不包含任何内容，您也必须将它们包含在代码中。因此，如果要实现MouseListener，则必须覆盖以下5种方法：

new DataAccessException("...") {}

顺便说一下，你不能只使用一个ActionListener，你正在尝试做什么？

Answer 2

不太确定这是否是问题，但该类中是否应该有一个mouseEntered方法来覆盖？

如何使用鼠标监听器调用另一个类？

2 个答案: