"搜索结果"打开一张桌子,在每一行的末尾都有一个"电子邮件按钮"。访问者点击一个"电子邮件按钮"并且系统向注册的"用户"。
发送电子邮件PHPMailer和邮件系统工作正常,但只能使用静态电子邮件!
问题:我需要更改代码以将电子邮件发送到访问者选择的单个电子邮件。我添加了一个" WHERE"条件到$query
,但似乎没有影响。
使用以下两条线的邮件功能
$mail->AddAddress("support@domain.co.uk", "John Doe");
$mail->AddAddress("admin@domain.co.uk");
以下行是不工作
$mail->AddAddress("$email", "John Doe");
错误消息说:
"地址无效:无法发送消息。"
"邮件程序错误:您必须至少提供一个收件人电子邮件地址。"
<?php
//mailer.php
$dbhost = 'xxx.xxx.xxx.xxx';
$dbuser = 'user_name';
$dbpass = 'password';
$dbtable = 'tablename';
$db = 'db_name';
$conn = mysqli_connect($dbhost,$dbuser,$dbpass,$db) or
die("Could not connect: " . mysql_error());
mysqli_select_db($conn,$db);
if(isset($_POST['requestedEmail'])){
$requestedEmail = $_POST['requestedEmail'];
}
//Connecting to database
$link = mysqli_connect($dbhost, $dbuser, $dbpass, $db) OR DIE ("Unable to connect to database! Please try again later.");
mysqli_select_db($conn,$db);
//Fetching from database table.
$query = "SELECT email FROM db_name WHERE email='". $requestedEmail . "'";
if ($result)
{
while ($row = mysqli_fetch_array($result)) {
send_mail($row['email']);
}
}
//$email = $row['email'];
?>
<?php
require 'PHPMailer_5.2.0/class.phpmailer.php';
$email = $row['email'];
$mail = new PHPMailer();
$mail->IsSMTP(); // set mailer to use SMTP
$mail->Host = "domainname.co.uk;domainname.co.uk"; // specify main and back`enter code here`up server
$mail->SMTPAuth = true; // turn on SMTP authentication
$mail->Username = "support@domain.co.uk"; // SMTP username
$mail->Password = "password"; // SMTP password
$mail->From = "support@domain.co.uk";
$mail->FromName ="Company Name";
$mail->AddAddress($email, "John Doe");
$mail->AddReplyTo("info@domain.co.uk", "Information");
$mail->WordWrap = 50; // set word wrap to 50 characters
$mail->IsHTML(true); // set email format to HTML
$mail->Subject = "Here is the subject 3.4";
$mail->Body = "This is the HTML message body <b>in bold!</b>";
$mail->AltBody = "This is the body in plain text for non-HTML mail clients";
if(!$mail->Send())
{
echo "Message could not be sent. <p>";
echo "Mailer Error: " . $mail->ErrorInfo;
exit;
}
echo "Message has been sent to: " . $email; // $email is not printed out
?>
答案 0 :(得分:0)
这似乎不对
$query = "SELECT email FROM db_name WHERE email=$row[email]";
从哪里获取$ row [email]?你需要在那里有一个有效的变量 - 例如从post数组(你正在从表单中传递变量)。类似的东西:
if(isset($_POST['requestedEmail'])){
$requestedEmail = $_POST['requestedEmail']}
// other code
$query = "SELECT email FROM db_name WHERE email='". $requestedEmail . "';
然后从返回的$行中获取电子邮件(假设您正在使用返回的查询中的该变量
$email = $Row['email'];
然后你可以使用$ email(没有引号,因为它是一个变量而不是一个字符串):
$mail->AddAddress($email, "John Doe");
答案 1 :(得分:-1)
这一行:
getContentScrim().getAlpha()
应改为:
$mail->AddAddress("$email", "John Doe");
在PHP中将变量作为参数传递时,不要像传递字符串那样在变量周围使用引号。因此,在您的代码中,您没有传递变量$ email,而是传递字符串“$ email”。