Question

每次编译这段代码时，我都希望它能够遍历每个“if，elif”，直到找到匹配。因此它可以继续在屏幕上打印出给定的列表。

但令我惊讶的是，即使您输入“步枪”，它所做的只是给你“其他”声明。

这是我在Stackoverflow上的第一篇文章，如果我犯了一些错误，请原谅我。

非常感谢任何帮助，提前谢谢。

rifles = ["Ak47", "M4A1", "Aug", "Famas", "Galil"]
pistols = ["Glock", "USP", "Deagle", "P250", "Five-7", "Tec-9"]
shotguns = ["Buckshot", "Benelli", "M1319", "Sawed-Off"]
snipers = ["AWP", "SSG", "Cheytac", "Barret", "M24"]
grenades = ["Smoke", "High-Explosive", "Flash", "Concussion", "Molotov", "Incendiary"]
knives = ["Bayonette", "Karambit", "Machete", "Butterfly", "Katana"]
equipment = ["Kevlar", "Helmet", "Tactical-Shield", "Boots", "Nightvision"]

raw_input = input("Search: ")


def search():

    if raw_input == "Rifles":
        for ri in rifles:

            print(ri)
            break
    elif raw_input is "Pistols":
        for pi in pistols:

            print(pi)
            break
    elif raw_input is "Shotguns":
        for sho in shotguns:

            print(sho)
            break
    elif raw_input is "Snipers":
        for sni in snipers:

            print(sni)
            break
    elif raw_input is "Grenades":
        for gre in grenades:

            print(gre)
            break
    elif raw_input is "Knives":
        for kni in knives:

            print(kni)

    elif raw_input is "Equipment":
        for equ in equipment:

            print(equ)
    else:

        print("Try again...")
    return
search()

Answer 1

在打印一个元素后，您正在打破每个循环。

SKStoreProductParameterAffiliateToken

你真的不需要休息，所以当你输入“Rifles”时摆脱它和it will work

Answer 2

您的代码可以用更简洁的方式表达，并且＆＃34; pythonic＆＃34;方式：

guns = {
    "rifles"   : ["Ak47", "M4A1", "Aug", "Famas", "Galil"],
    "pistols"  : ["Glock", "USP", "Deagle", "P250", "Five-7", "Tec-9"],
    "shotguns" : ["Buckshot", "Benelli", "M1319", "Sawed-Off"],
    "snipers"  : ["AWP", "SSG", "Cheytac", "Barret", "M24"],
    "grenades" : ["Smoke", "High-Explosive", "Flash", "Concussion", "Molotov", "Incendiary"],
    "knives"   : ["Bayonette", "Karambit", "Machete", "Butterfly", "Katana"],
    "equipment": ["Kevlar", "Helmet", "Tactical-Shield", "Boots", "Nightvision"],
}

gun = raw_input("Search: ")
gun = gun.lower()

try:
    print guns[gun]
except KeyError:
    print "No gun of type %s" % gun

Answer 3

但令我惊讶的是，即使您输入步枪＆＃34;，它所做的只是给你＆＃34;否则＆＃34;言。

您的代码会检查"Rifles"，而不是"rifles"。如果你希望两者比较相等，你需要规范化字母大小写，例如，如下：

if raw_input.lower() == "rifles":
    for ri in rifles:
        ...

Python代码跳过if和elif down to else

3 个答案: