我是使用python的新手,我想知道如何使用python从我的json文件中打印一些值,以下是我的json文件
{
"igt@gem_reloc_overflow@single-overflow": {
"__type__": "TestResult",
"command": "/home/gfx/intel-graphics/intel-gpu-tools/tests/gem_reloc_overflow --run-subtest single-overflow",
"dmesg": "",
"environment": "PIGLIT_PLATFORM=\"mixed_glx_egl\" PIGLIT_SOURCE_DIR=\"/home/gfx/intel-graphics/intel-gpu-tools/piglit\"",
"err": "(gem_reloc_overflow:19562) CRITICAL: Test assertion failure function reloc_tests, file gem_reloc_overflow.c:260:\n(gem_reloc_overflow:19562) CRITICAL: Failed assertion: __gem_execbuf(fd, &execbuf) == -14\n(gem_reloc_overflow:19562) CRITICAL: error: -22 != -14\nSubtest single-overflow failed.\n**** DEBUG ****\n(gem_reloc_overflow:19562) DEBUG: relocation_count=4294967295\n(gem_reloc_overflow:19562) CRITICAL: Test assertion failure function reloc_tests, file gem_reloc_overflow.c:260:\n(gem_reloc_overflow:19562) CRITICAL: Failed assertion: __gem_execbuf(fd, &execbuf) == -14\n(gem_reloc_overflow:19562) CRITICAL: error: -22 != -14\n**** END ****\n",
"exception": null,
"out": "IGT-Version: 1.14-g1e9a3ac (x86_64) (Linux: 4.6.0-rc4-drm-intel-nightly-ww17-commit-1e81bac+ x86_64)\nStack trace:\n #0 [__igt_fail_assert+0x101]\n #1 [reloc_tests+0x6d6]\n #2 [<unknown>+0x6d6]\nSubtest single-overflow: FAIL (8.469s)\n",
"pid": 19562,
"result": "fail",
"returncode": 99,
"subtests": {
"__type__": "Subtests"
},
"time": {
"__type__": "TimeAttribute",
"end": 1462072402.5360818,
"start": 1462072393.7328644
},
"traceback": null
}
}
我需要的值是“结果:失败”。
到目前为止,我有这段代码:
import json
with open("9.json") as json_file:
json_data = json.load(json_file)
print(json_data)
thaks
答案 0 :(得分:1)
json.load
函数返回一个字典(类型为dict
的对象)。
字典将密钥与线索相关联。要访问字典中的值,可以使用以下语法:
value = dictionary[key]
在您的特定情况下:
result = json_data['result']
答案 1 :(得分:1)
给它一个机会!
for key, value in json_data.iteritems():
result = value['result']
print result
更新(评论中的问题):
如果您有多个文件并希望一次存储所有信息 - 请尝试将其全部放入字典中。这取决于您想要密钥的内容。但试试这个(这将创建一个{json_key: result_value}
all_results = {}
json_file_list = ['file_1.json', 'file_2.json']
for file in json_file_list:
with open(file) as json_file:
json_data = json.load(json_file)
for key, value in json_data.iteritems():
if 'result' in value:
all_results[key] = value['result']
return all_results
答案 2 :(得分:0)
json_data["igt@gem_reloc_overflow@single-overflow"]["result"]
这将打印结果
答案 3 :(得分:0)
json数据存储为python字典。
因此您可以访问&#34;结果&#34;的值。如下:
json_data["igt@gem_reloc_overflow@single-overflow"]["result"]
W.R.T您的代码:
import json
with open("9.json") as json_file:
json_data = json.load(json_file)
print(json_data["igt@gem_reloc_overflow@single-overflow"]["result"])