Question

我正在对包含各种客户订单的数据库执行以下查询。

SELECT WEEKDAY(orderDateTime) Date, COUNT(clientID) totalCount FROM orders WHERE YEARWEEK(orderDateTime,1) = YEARWEEK(NOW(),1) GROUP BY DATE(orderDateTime)

SELECT WEEKDAY(orderDateTime) Date, COUNT(clientID) totalCount FROM orders WHERE YEARWEEK(orderDateTime,1) = YEARWEEK(NOW() - INTERVAL 1 WEEK,1) GROUP BY DATE(orderDateTime)

SELECT DATE_FORMAT(orderDateTime, '%Y') as 'year', DATE_FORMAT(orderDateTime, '%m') as 'month', COUNT(clientID) as 'total' FROM orders GROUP BY DATE_FORMAT(orderDateTime, '%Y%m')

我是他们将这些构建成一个数组，其中月/日数与计算值相对应：

[[0,1]，[1,4] ...]

我正在使用Flot来绘制这些图形，但是发生的事情是，没有任何订单没有任何价值的任何日子或月份（显然）所以你得到的是这样的：

[[0,1]，[1,4]，[6,12]]使图形图错误。

试图解决的是如何填充它看起来像：

[[0,1]，[1,4]，[2,0]，[3,0]，[4,0]，[5,0]，[6,12]]＆lt;对于工作日而言，

[[1,1]，[2,4]，[3,0]，[4,0]，[5,0]，[6,0]，[7,12]，[8,0] ]，[9,12]，[10,0]，[11,0]，[12,0]]＆lt; - 每个月。

我使用PHP作为主要的咕噜声。如果我不清楚，任何指针都会受到赞赏和抱歉。询问您是否需要澄清。

PHP：

$thisWeekA = array();

$thisWeekQ = $database->query("SELECT WEEKDAY(orderDateTime) Date, COUNT(clientID) totalCount FROM orders WHERE YEARWEEK(orderDateTime,1) = YEARWEEK(NOW(),1) GROUP BY DATE(orderDateTime)")->fetchAll();

foreach($thisWeekQ as $thisweek){
    $thisWeekA[] = array( $thisweek['Date'], $thisweek['totalCount'] );
}

array(2) {
  [0]=>
  array(4) {
    ["Date"]=>
    string(1) "2"
    [0]=>
    string(1) "2"
    ["totalCount"]=>
    string(1) "3"
    [1]=>
    string(1) "3"
  }
  [1]=>
  array(4) {
    ["Date"]=>
    string(1) "3"
    [0]=>
    string(1) "3"
    ["totalCount"]=>
    string(1) "2"
    [1]=>
    string(1) "2"
  }
}

Answer 1

每周数据用于循环在你的php更新它，逻辑仅在一周内7天而不是从结果数据中使用foreach我们可以使用for循环七天

即同样多年使用

$thisWeekA = array();    
$thisWeekQ = $database->query("SELECT WEEKDAY(orderDateTime) Date, COUNT(clientID) totalCount FROM orders WHERE YEARWEEK(orderDateTime,1) = YEARWEEK(NOW(),1) GROUP BY DATE(orderDateTime)")->fetchAll();

    for ($i = 0; $i <= 6; $i++) {
        if ($thisWeekQ[$i]['Date'] == $i) {
            $thisWeekA[$i][] = array($thisWeekQ[$i]['Date'], $thisWeekQ[$i]['totalCount']);
        } else {
            $thisWeekA[$i][] = array($i, 0);
        }
    }

Answer 2

您可能想要考虑更像这样构建数组：

var dow = [];
dow[0] = 1;
dow[1] = 4;
dow[6] = 12;

此时，您可以为图表填充数组

var chartData = [];
for (var i=0; i<7; i++){
    chartData[i] = [i, (dow[i] === undefined ? 0 : dow[i])];
}

Answer 3

我设法找到了一种方法。谢谢你指点我的For循环方向！

这就是我想出来的并且有效！

function arrayhunt($products, $field, $value){

   foreach($products as $key => $product){

        if ($product[$field] == $value){
            return $key;
        }
   }
   return false;
}


    $i = 0;
    for ($i = 0; $i <= 6; $i++) {

        $keys = arrayhunt($thisWeekQ,"Date",$i);

        if($keys !== FALSE){
            $thisWeekA[] = array($thisWeekQ[$keys]['Date'], $thisWeekQ[$keys]['totalCount']);
        } else {
            $thisWeekA[] = array($i, 0);
        }

        $keys = "";
    }

希望以后有人发现这个有用。

向数组添加零值

3 个答案: