Question

我有这段代码，我的问题是除非我点击 Enter 键，否则Scanner没有拿起最后一行。

我已经尝试了所有答案，但没有运气。我无法使用BufferedReader，我必须仅使用Scanner执行此操作。

Scanner scanner = new Scanner(System.in);
int noOfCases = scanner.nextInt();
scanner.nextLine();                  //consuming the left out \n
for (int i = 1; i <= noOfCases; i++) {
    int count = 0;
    String line = scanner.nextLine();
    String arr[] = line.split(" ");
    int white = Integer.parseInt(arr[0]);
    int red = Integer.parseInt(arr[1]);
    int green = Integer.parseInt(arr[2]);

    if (white > 0 && red > 0 && green > 0) {
        count = count + (white / 3) + (red / 3) + (green / 3);
        white = white - ((white / 3) * 3);
        red = red - ((red / 3) * 3);
        green = green - ((green / 3) * 3);
    }
    int minVal = Math.min(Math.min(white, red), green);
    count = count + minVal;

    System.out.println(count);
}

上面的代码没有读取最后一行，传递的输入不在我手中。

示例输入类似于（测试用例后跟测试用例的数量）：

3        // no of test cases
5 5 5
10 4 2
4 4 4

Answer 1

由于某些原因，除非您按Enter键以帮助构建扫描仪，否则不会定义最后一行。 nextInt()可能就足够了。

public static void main(String[] args) {
    Scanner scanner=new Scanner(System.in);
    int noOfCases=scanner.nextInt();
    scanner.nextLine();                  //consuming the left out \n
    for(int i=1;i<=noOfCases;i++)
    {
    int count=0;
    int white=scanner.nextInt();
    int red=scanner.nextInt();
    int green=scanner.nextInt();

    if(white>0&&red>0&&green>0)
    {
        count=count+(white/3)+(red/3)+(green/3);
        white=white-((white/3)*3);
        red=red-((red/3)*3);
        green=green-((green/3)*3);
    }
    int minVal=Math.min(Math.min(white,red),green);
    count=count+minVal;

    System.out.println(count);

    }
}

扫描仪没有读到最后一行

1 个答案: