所以我正在学习如何从一个网站制作一个tic tac toe游戏，当我完成时，我无法播放它，因为我一直得到同样的错误，我检查了我的工作，一切都很好，这里和＃39;是代码
import random
from time import sleep
print "To play this game, you use your 1-9 keys"
print "This is layout of each number representing a square"
print "7|8|9"
print "4|5|6"
print "1|2|3"
print " "
def drawboard(board): #Draws the board
print "Board"
print '' + board[7] + '|' + board[8] + '|' + board[9]
print '' + board[4] + '|' + board[5] + '|' + board[6]
print '' + board[1] + '|' + board[2] + '|' + board[3]
def inputplayerletter(): #Asks player if they want to be X or O
letter = ''
while not letter == 'X' or letter == 'O':
print "Do you want to be X or O?"
letter = raw_input(" ").upper()
if letter == 'X':
return ['X', 'O']
else:
return ['O', 'X']
def whogoesfirst(): #This determines who goes first
if random.randint(0,1) == '0':
return 'computer'
else:
return 'player'
def playagain(): #Asks player if it wants to play again
print "Do you want to play again?(Y/N)"
return raw_input("").lower().startswith('y')
def makemove(board, letter, move): #When someone makes a move we execute this function
board[move] = letter
def winner(bo,le): #Determines whose the winner
return ((bo[7] == le and bo[8] == le and bo[9] == le) or
(bo[4] == le and bo[5] == le and bo[6] == le) or
(bo[1] == le and bo[2] == le and bo[3] == le) or
(bo[7] == le and bo[4] == le and bo[1] == le) or
(bo[8] == le and bo[5] == le and bo[2] == le) or
(bo[9] == le and bo[6] == le and bo[3] == le) or
(bo[7] == le and bo[5] == le and bo[3] == le) or
(bo[9] == le and bo[5] == le and bo[1] == le)
def getboardcopy(board): #Creates a copy of the board for the computer AI
dupeboard = []
for i in dupeboard:
dupeboard.append(i)
return dupeboard
def isspacefree(board, move): #Checks if space is free.
return board[move] == ''
def playermove(board): #Where the player inputs his/her move
move = ''
while move not in '1 2 3 4 5 6 7 8 9'.split() or not isspacefree(board, int(move)):
print "your move (Pick from 1-9)"
move = raw_input("")
return int(move)
def choosemovefromlist(board, movelist): #chooses possible moves from list
possiblemoves = []
for i in moveslist:
if isspacefree(board, i):
possiblemoves.append(i)
if len(possiblemoves) != 0:
return random.choice(possiblemove)
else:
return None
def computerai(board, computerletter): #Computer AI
if computerletter == 'X':
playerletter = 'O'
else:
playerletter = 'X'
for i in range(1,10):
dupe = getboardcopy(board)
if isspacefree(copy, i):
makemove(board, computerletter, i)
if winner(copy, computerletter):
return i
for i in range(1,10):
dupe = getboardcp[y(board)
if isspacefree(copy, i):
makemove(board, playerletter, i)
if winner(copy, playerletter):
return i
move = choosemovefromlist(board, [1, 3, 7, 9])
if move != None:
return move
if isspacefree(board, 5):
return 5
return choosemovefromlist(board[2,4,6,8])
def isboardfull(board):
for i in range(1,10):
if isspacefree(board, i):
return False
return True
print "Welcome to Tic Tac Toe!"
while True:
theboard = [''] * 10
print "Flipping the coin..."
sleep(2)
turn = whogoesfirst()
print "The " + turn + " goes first."
gameinprogress = True
while gameinprogress:
if turn == 'player':
drawboard(theboard)
move = getplayermove(theboard)
makemove = (theboard, playerletter, move)
if winner(theboard, playerletter):
drawboard(theboard)
print "The player wins the game! Congratulations!"
gameinprogress = False
else:
if isboardfull(theboard):
drawboard(theboard)
print "Tie game! No one wins!"
break
else:
turn = 'computer'
else:
move = computerai(theboard, computerletter)
makemove(theboard, computerletter, move)
if winner(theboard, computerletter):
drawboard(theboard)
print "The computer has beaten the player!"
break
else:
turn = 'player'
if not playagain():
break
我一直在收到错误：
def getboardcopy(board): #Creates a copy of the board for the computer AI
dupeboard = []
for i in dupeboard:
dupeboard.append(i)
return dupeboard
def isspacefree(board, move): #Checks if space is free.
return board[move] == ''
def playermove(board): #Where the player inputs his/her move
move = ''
while move not in '1 2 3 4 5 6 7 8 9'.split() or not isspacefree(board, int(move)):
print "your move (Pick from 1-9)"
move = raw_input("")
return int(move)
def choosemovefromlist(board, movelist): #chooses possible moves from list
possiblemoves = []
for i in moveslist:
if isspacefree(board, i):
possiblemoves.append(i)
if len(possiblemoves) != 0:
return random.choice(possiblemove)
else:
return None
def computerai(board, computerletter): #Computer AI
if computerletter == 'X':
playerletter = 'O'
else:
playerletter = 'X'
for i in range(1,10):
dupe = getboardcopy(board)
if isspacefree(copy, i):
makemove(board, computerletter, i)
if winner(copy, computerletter):
return i
for i in range(1,10):
dupe = getboardcp[y(board)
if isspacefree(copy, i):
makemove(board, playerletter, i)
if winner(copy, playerletter):
return i
move = choosemovefromlist(board, [1, 3, 7, 9])
if move != None:
return move
if isspacefree(board, 5):
return 5
return choosemovefromlist(board[2,4,6,8])
def isboardfull(board):
for i in range(1,10):
if isspacefree(board, i):
return False
return True
print "Welcome to Tic Tac Toe!"
即使我在此删除已定义的函数，也会出现另一个错误。
因此，当我正常运行代码时，这就是我得到的错误
Traceback (most recent call last):
File "python", line 49
def getboardcopy(board): #Creates a copy of the board for the computer AI
^
SyntaxError: invalid syntax
因此，当我从代码中删除定义的函数时，我收到此错误：
Traceback (most recent call last):
File "python", line 50
def isspacefree(board, move): #Checks if space is free.
^
SyntaxError: invalid syntax
即使我删除了该函数，在此函数之后函数也会发生同样的错误，然后如果我从def getboardcopy开始删除每个函数，我的print语句出错。然后当我删除时，我从while循环中得到另一个错误。我使用的是Python 2.7.2
答案 0 :(得分：1)
即使这应该是关闭的，这也是一个很好的学习机会。当你得到那种类型的级联错误时，通常意味着错误信息之上的某些东西是不平衡的。
您应该能够分辨的另一种方式是，每次按下回车键时，光标都不会达到您预期的结束位置。
所以指出的错误是
def winner(bo,le): #Determines whose the winner
return ((bo[7] == le and bo[8] == le and bo[9] == le) or
(bo[4] == le and bo[5] == le and bo[6] == le) or
(bo[1] == le and bo[2] == le and bo[3] == le) or
(bo[7] == le and bo[4] == le and bo[1] == le) or
(bo[8] == le and bo[5] == le and bo[2] == le) or
(bo[9] == le and bo[6] == le and bo[3] == le) or
(bo[7] == le and bo[5] == le and bo[3] == le) or
(bo[9] == le and bo[5] == le and bo[1] == le)) <- this was missing
答案 1 :(得分：0)
存在大量语法错误并调用不存在的变量。该程序也在主while循环中缺少对inputplayerletter（）的调用。它现在将运行，但您需要修复仍然存在的所有逻辑问题。
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public class RequestExceptionHandler extends ResponseEntityExceptionHandler {
@Override
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MyCustomErrorResource error = new MyCustomErrorResource("missing parameter");
return handleExceptionInternal(ex, error, headers, status, request);
}
}