如何在一个字段更改的表单数据中输入mySQL中的多行

Question

我有一份表格，询问有关工作的一些基本问题，然后要求进入的人列出当时与他们在一起的所有同事。我想要做的是让所有在场的同事都输入一行数据 - 所以其他所有细节都保持不变，除了他们的work_id（这是人的标识符）。我的代码似乎向db提交了1行，其中workID字段为空

<?php
require_once('includes/dbconnect.php');

$varWorkID = $_POST['workid'];
$varDate = $_POST['date'];
$varType = $_POST['type'];
$varSuper = $_POST['supervisor'];
$varReference = $_POST['reference'];

//Remove last part of array as extra 1 sent through by form 
$workID = array_pop($varWorkID);

for ($i=0; $i < count($workID); $i++ )
{
    mysqli_query($conn,"INSERT INTO searches (workid,date,type,super,reference) VALUES('".$workID."','".$varDate."','".$varType."','".$varSuper."','".$varReference."')");
}
echo "Completed";

我认为我相当接近，但我只需要为每个在职员工填写workid以填充每个工作ID。

非常感谢任何帮助

Answer 1

这里的问题是你在进入循环$workID = array_pop($varWorkID);之前调用for ($i=0; $i < count($workID); $i++ )，所以PHP解释器认为你只想迭代那个元素的长度。你真正想要做的是在循环内部时从阵列中弹出一个元素。

<?php
require_once('includes/dbconnect.php');

$varWorkID = $_POST['workid'];
$varDate = $_POST['date'];
$varType = $_POST['type'];
$varSuper = $_POST['supervisor'];
$varReference = $_POST['reference'];


// iterate over the count of the whole array $varWorkID = $_POST['workid']
for ($i=0; $i < count($varWorkID); $i++ )
{
    // now pop off the array inside the loop
    //Remove last part of array as extra 1 sent through by form 
    $workID = array_pop($varWorkID);
    mysqli_query($conn,"INSERT INTO searches (workid,date,type,super,reference) VALUES('".$workID."','".$varDate."','".$varType."','".$varSuper."','".$varReference."')");
}
echo "Completed";

现在我认为@Dima Fitiskin's comment提出了一个更好的方法，因为你并不需要花费多少时间来调用另一个函数array_pop或者在堆栈$workID上抛出另一个变量＆＃ 39;已经有了循环内的索引$i的迭代引用。

<?php
require_once('includes/dbconnect.php');

$varWorkID = $_POST['workid'];
$varDate = $_POST['date'];
$varType = $_POST['type'];
$varSuper = $_POST['supervisor'];
$varReference = $_POST['reference'];


// iterate over the count of the whole array $varWorkID = $_POST['workid']
for ($i=0; $i < count($varWorkID); $i++ )
{
    mysqli_query($conn,"INSERT INTO searches (workid,date,type,super,reference) VALUES('".$varWorkID[$i]."','".$varDate."','".$varType."','".$varSuper."','".$varReference."')");
}
echo "Completed";