ddslick下拉表格帖子不起作用

时间:2016-04-30 15:34:56

标签: php jquery html

post方法不适用于下拉列表jquery ddslick

这是表格:

<?php 
if(isset($_POST['usern'])){
    $value = $_POST['usern'];
if($value > 0)
{
echo "work";
} 
else
{
echo "not work";
}
}
?>

    <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.18/jquery-ui.min.js"></script> <script type="text/javascript" src="http://web-0a54fa71-eb5f-4cdc-bfbe-142bcd20757b.runnablecodesnippets.com/jquery.ddslick.min.js"></script> <script type="text/javascript" src="http://web-0a54fa71-eb5f-4cdc-bfbe-142bcd20757b.runnablecodesnippets.com/script.js"></script>

        <form action='users.php?j=60' method='post'>

        <select id="demo-htmlselect-basic" form="post" name="usern">
        <option value="0">Select</option>
        <option data-imagesrc="image.jpg" value="1"> Part 1</option>
        <option data-imagesrc="image.jpg" value="2"> Part 2</option>
        <option data-imagesrc="image.jpg" value="1"> Part 3</option>
        </select>

<input type='submit' value='Send'>

        </form>

这是我使用的下拉菜单:http://code.runnable.com/UgC2a5sY1P8LAAAj/how-to-create-a-custom-drop-down-with-images-using-jquery-ui

1 个答案:

答案 0 :(得分:0)

让我有时间得到你想要的东西 你应该使用选择列表php cod中的值。我希望它可以帮助你的人

<?php 

$values = $_POST['list'];
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
if (isset($_POST['submit']) && ($_POST['submit'] == 'Submit')) {



echo $options[$value];
echo $values;
}
}

?>

<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.18/jquery-ui.min.js"></script> <script type="text/javascript" src="http://web-0a54fa71-eb5f-4cdc-bfbe-142bcd20757b.runnablecodesnippets.com/jquery.ddslick.min.js"></script> <script type="text/javascript" src="http://web-0a54fa71-eb5f-4cdc-bfbe-142bcd20757b.runnablecodesnippets.com/script.js"></script>



  <form  method='post'> don't forget add the action page 

        <select id="demo-htmlselect-basic" name="list">
        <option value="0" >Select</option>
        <option value="1" > Part 1</option>
        <option  value="2"> Part 2</option>
        <option value="3"> Part 3</option>
        </select>

      <input type="submit" name="submit" id="submit" value="Submit" />

        </form>