Question

任何人都可以帮助调试我的脚本!!我无法从json文件加载外部数据..它可以在代码中使用变量，但是当我在文件中将它们分开时......它不是!!

＆＃13;

<!DOCTYPE html>
<html>
<head>
	<meta charset='utf-8'>
    <title>tree 1</title>
     <style>

		.node {
		  cursor: pointer;
		}

		.node circle {
		  fill: #fff;
		  stroke: steelblue;
		  stroke-width: 1.5px;
		}

		.node text {
		  font: 10px sans-serif;
		}

		.link {
		  fill: none;
		  stroke: #ccc;
		  stroke-width: 1.5px;
		}
    </style>
</head>


<body>
	<script src='http://d3js.org/d3.v3.min.js'></script>
	<script type="text/javascript">
// ************** Generate the tree diagram	 *****************
		var diameter = 1000;

		var margin = {
		    top: 20,
		    right: 120,
		    bottom: 20,
		    left: 120
		  },
		  width = diameter,
		  height = diameter;

		var i = 0,
		  duration = 350,
		  root;

		var tree = d3.layout.tree()
		  .size([360, diameter / 2 - 80])
		  .separation(function(a, b) {
		    return (a.parent == b.parent ? 1 : 10) / a.depth;
		  });

		var diagonal = self.diagonal = d3.svg.line().interpolate('step')
		  .x(function(d) {
		    return d.x;
		  })
		  .y(function(d) {
		    return d.y;
		  });

		var svg = d3.select("body").append("svg")
		  .attr("width", width)
		  .attr("height", height)
		  .append("g")
		  .attr("transform", "translate(" + diameter / 2 + "," + diameter / 2 + ")");

		// load the external data
		d3.json("dataFile.json", function(error, dataFile) {
			root = dataFile;
			root.x0 = height / 2;
			root.y0 = 0;
			update(root);
		});

//root = pubs;
//root.x0 = height / 2;
//root.y0 = 0;

//root.children.forEach(collapse); // start with all children collapsed
//update(root);

d3.select(self.frameElement).style("height", "800px");

function update(source) {

  // Compute the new tree layout.
  var nodes = tree.nodes(root),
    links = tree.links(nodes);

  // Normalize for fixed-depth.
  nodes.forEach(function(d) {
    d.y = d.depth * 80;
  });

  // Update the nodes…
  var node = svg.selectAll("g.node")
    .data(nodes, function(d) {
      return d.id || (d.id = ++i);
    });

  // Enter any new nodes at the parent's previous position.
  var nodeEnter = node.enter().append("g")
    .attr("class", "node")
    //.attr("transform", function(d) { return "rotate(" + (d.x - 90) + ")translate(" + d.y + ")"; })
    .on("click", click);

  nodeEnter.append("circle")
    .attr("r", 1e-6)
    .style("fill", function(d) {
      return d._children ? "lightsteelblue" : "#fff";
    });

  nodeEnter.append("text")
    .attr("x", 10)
    .attr("dy", ".35em")
    .attr("text-anchor", "start")
    //.attr("transform", function(d) { return d.x < 180 ? "translate(0)" : "rotate(180)translate(-" + (d.name.length * 8.5)  + ")"; })
    .text(function(d) {
      return d.name;
    })
    .style("fill-opacity", 1e-6);

  // Transition nodes to their new position.
  var nodeUpdate = node.transition()
    .duration(duration)
    .attr("transform", function(d) {
      return "rotate(" + (d.x - 90) + ")translate(" + d.y + ")";
    })

  nodeUpdate.select("circle")
    .attr("r", 4.5)
    .style("fill", function(d) {
      return d._children ? "lightsteelblue" : "#fff";
    });

  nodeUpdate.select("text")
    .style("fill-opacity", 1)
    .attr("transform", function(d) {
      return d.x < 180 ? "translate(0)" : "rotate(180)translate(-" + (d.name.length + 50) + ")";
    });

  // TODO: appropriate transform
  var nodeExit = node.exit().transition()
    .duration(duration)
    .attr("transform", function(d) {
      return "diagonal(" + source.y + "," + source.x + ")";
    })
    .remove();

  nodeExit.select("circle")
    .attr("r", 1e-6);

  nodeExit.select("text")
    .style("fill-opacity", 1e-6);

  // Update the links…
  var link = svg.selectAll("path.link")
    .data(links, function(d) {
      return d.target.id;
    });

  // Enter any new links at the parent's previous position.
  link.enter().append('svg:path', 'g')
    .duration(self.duration)
    .attr('d', function(d) {
      return self.diagonal([{
        y: d.source.x,
        x: d.source.y
      }, {
        y: d.target.x,
        x: d.target.y
      }]);
    });

  // Transition links to their new position.
  link.transition()
    .duration(duration)
    .attr("d", diagonal);

  // Transition exiting nodes to the parent's new position.
  link.exit().transition()
    .duration(duration)
    .attr("d", function(d) {
      var o = {
        x: source.x,
        y: source.y
      };
      return diagonal({
        source: o,
        target: o
      });
    })
    .remove();

  // Stash the old positions for transition.
  nodes.forEach(function(d) {
    d.x0 = d.x;
    d.y0 = d.y;
  });
}

// Toggle children on click.
function click(d) {
  if (d.children) {
    d._children = d.children;
    d.children = null;
  } else {
    d.children = d._children;
    d._children = null;
  }

  update(d);
}

// Collapse nodes
function collapse(d) {
  if (d.children) {
    d._children = d.children;
    d._children.forEach(collapse);
    d.children = null;
  }
}



	</script>
</body>

</html>

＆＃13;

＆＃13; 作为一个json，我用这个文件测试！

＆＃13;

  {
  "name": "Top Level",
  "parent": "null",
  "children": [
    {
      "name": "Level 2: A",
      "parent": "Top Level",
      "children": [
        {
          "name": "Son of A",
          "parent": "Level 2: A"
        },
        {
          "name": "Daughter of A",
          "parent": "Level 2: A"
        }
      ]
    },
    {
      "name": "Level 2: B",
      "parent": "Top Level"
    }
  ]
}
;

＆＃13;

谢谢！

Answer 1

你的json最后有一个;

Plunkr demo

D3.js树图表外部数据导入调试

1 个答案: