Question

我有一个像这样的字符串数组。

var items= ['products/600/application/286/tabbed/301/text',
            'products/600/application/286/tabbed/305/text',
            'products/600/application/500/tabbed/200/text',
            'products/600/application/500/tabbed/300/text',
            'products/600/application/286/tinytext',
            'products/600/differenttext'];

我需要用连续数字替换数字（相同的数字应该相同），输出应该如下所示：

 var items= ['products[1]/application[1]/tabbed[1]/text',
                'products[1]/application[1]/tabbed[2]/text',
                'products[1]/application[2]/tabbed[1]/text',
                'products[1]/application[2]/tabbed[2]/text',
                'products[1]/application[1]/tinytext',
                'products[1]/differenttext'];

请注意，相同的数字应该得到相同的结果，例如，所有286应该是[1]因为它是最低的而500应该被[2]替换，因为它是垂直中的下一个更大的数字。把它们想象成孩子。例如，对于行

products/600/application/286/tabbed/301/text,
products/600/application/286/tabbed/305/text,

直到tabbed，但在此之后，有2个不同的孩子，第一个人的身份是301秒是305.所以他们应该[1]和[2]。现在看一下行

products/600/application/286/tabbed/305/text,
products/600/application/500/tabbed/200/text, 
products/600/application/500/tabbed/300/text,

在这种情况下，应用程序有两个孩子。 286和500.第二个是500，有2个孩子。所以500的孩子应该是1和2（200和300）

申请temp= items[0].match(/\d+/g);后，我得到了结果[600,286,301]。我应该使用json对象来放置temp得到的所有结果，还是使用2d数组？

Answer 1

您可以使用 map() 和 replace()

执行此类操作

var items = ['products/600/application/286/tabbed/301/text',
  'products/600/application/286/tabbed/305/text',
  'products/600/application/500/tabbed/200/text',
  'products/600/application/500/tabbed/300/text',
  'products/600/application/286/tinytext',
  'products/600/differenttext'
];
var num = {};

var res = items.map(function(v, i) { // iterate over the array for generating updated array
  return v.replace(/\/(\d+)\/(?:(.*?)\/(\d+)\/(?:(.*?)\/(\d+)\/)?)?/, function(m, m1, m2, m3, m4, m5) { //find the number to replace
    var str = replace(m1, 'main', 0);
    if (m3) {
      str += m2 + replace(m3, m1);
      if (m5)
        str += m4 + replace(m5, m1 + '_' + m3);
    }
    return str;
  });
});

function replace(mat, ind1) {
  if (!num[ind1])
    num[ind1] = {
      ind: 0
    };
  if (num[ind1][mat]) // check index already defined
    return '/[' + num[ind1][mat] + ']/'; // if defined use the previous
  num[ind1][mat] = ++num[ind1].ind ;// else update index in object
  return '/[' + num[ind1].ind + ']/'; // and return the replace string
}

document.write('<pre>' + JSON.stringify(res, null, 3) + '</pre>');

更新： 如果出现次数超过3，那么你可以这样做，

var items = ['products/600/application/286/tabbed/301/text/222/kjkjk',
  'products/600/application/286/tabbed/301/text/112/kjkjk',
  'products/600/application/286/tabbed/305/text/222/kjkjk',
  'products/600/application/500/tabbed/200//text/222/kjkjk',
  'products/600/application/500/tabbed/300/text',
  'products/600/application/286/tinytext',
  'products/600/differenttext'
];
var num = {};

var res = items.map(function(v, i) { // iterate over the array for generating updated array
  var match = 'match';
  return v.replace(/\/(\d+)\//g, function(m, m1) {
    var res = replace(match, m1);
    match += '_' + m1;
    return res;
  });
});
78

function replace(ind1, m1) {
  if (!num[ind1])
    num[ind1] = {
      ind: 0
    };
  if (!num[ind1][m1])
    num[ind1][m1] = ++num[ind1].ind;
  return '/[' + num[ind1][m1] + ']/';
}

document.write('<pre>' + JSON.stringify(res, null, 3) + '</pre>');

替换字符串数组javascript中的数字

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