如何在R

时间:2016-04-30 04:45:52

标签: r

我有一个名为mydf的数据框。我的下面的代码绘制了Y轴效率图的混合组合。我想要做的是替换每个样品组合(每条线)的X轴测量值,以便由测量柱表示。因此,对于efficiency1,我希望它由measurement1列中的值精确表示,而不是代码中的一般1到7测量值,我希望通过各自的测量对所有效率级别执行此操作列。有人可以帮我实现这个目标。

  mydf<-structure(list(sample_A = structure(c(1L, 2L, 2L, 2L, 3L, 4L), .Label = c("2568", 
    "2669", "2670", "2671", "2946", "LPH-001-10_AK1", "LPH-001-12_AK2", 
    "LPH-001-9"), class = "factor"), sample_B = structure(c(1L, 2L, 
    3L, 4L, 3L, 4L), .Label = c("2568", "2669", "2670", "2671", "2946", 
    "LPH-001-10_AK1", "LPH-001-12_AK2", "LPH-001-9"), class = "factor"), 
        efficiency1 = c(1.02, 0.964, 0.415, 0.422, 0.98, 0.986), 
        efficiency2 = c(1, 0.944, 0.395, 0.402, 0.96, 0.966), efficiency3 = c(0.9, 
        0.844, 0.295, 0.302, 0.86, 0.866), efficiency4 = c(0.32, 
        0.264, -0.285, -0.278, 0.28, 0.286), efficiency5 = c(0.02, 
        -0.0360000000000001, -0.585, -0.578, -0.0200000000000001, 
        -0.0140000000000001), efficiency6 = c(0.12, 0.0639999999999999, 
        -0.485, -0.478, 0.08, 0.086), efficiency7 = c(0.02, -0.036, 
        -0.585, -0.578, -0.02, -0.014), measurement1 = c(1, 1.2, 
        1, 1.3, 1.3, 1), measurement2 = c(2, 2.1, 2, 2.2, 2.3, 2), 
        measurement3 = c(3, 3.1, 3, 3.2, 3.3, 3), measurement4 = c(4, 
        4.1, 4, 4.2, 4.3, 4.1), measurement5 = c(5.1, 5.1, 4, 4.2, 
        4.3, 4.1), measurement6 = c(5.1, 6.1, 6, 6.2, 6.3, 6.1), 
        measurement7 = c(7.1, 7.1, 7, 7.2, 6.3, 7.1)), .Names = c("sample_A", 
    "sample_B", "efficiency1", "efficiency2", "efficiency3", "efficiency4", 
    "efficiency5", "efficiency6", "efficiency7", "measurement1", 
    "measurement2", "measurement3", "measurement4", "measurement5", 
    "measurement6", "measurement7"), row.names = c(NA, 6L), class = "data.frame")

我的代码:

effCis <- grep('^efficiency',names(mydf));
xlim <- c(1,length(effCis));
ylim <- range(mydf[,effCis],na.rm=T);
ylim[1L] <- floor(ylim[1L]/0.1)*0.1;
ylim[2L] <- ceiling(ylim[2L]/0.1)*0.1;
xticks <- seq_along(effCis);
yticks <- seq(ylim[1L],ylim[2L],0.1);
plot(NA,xlim=xlim,ylim=ylim,xlab='measurement',ylab='efficiency',xaxs='i',yaxs='i',axes=F);
abline(v=xticks,col='lightgrey');
abline(h=yticks,col='lightgrey');
abline(h=0,lwd=2);
axis(1L,xticks,xticks,font=2L,cex.axis=0.7);
axis(2L,yticks,sprintf('%.1f',yticks),las=1L,font=2L,cex.axis=0.7);
hybrid.col <- data.frame(hybrid=seq_len(nrow(mydf)),col=c('red','green','blue','gold','cyan','magenta'),stringsAsFactors=F);
splineN <- 200L;
for (ri in seq_len(nrow(hybrid.col))) {
    hybrid <- hybrid.col$hybrid[ri];
    col <- hybrid.col$col[ri];
    x <- xticks;
    y <- c(as.matrix(mydf[hybrid,effCis]));
    points(x,y,pch=16L,col=col,xpd=NA);
    with(spline(x,y,splineN),{
        lines(x,y,col=col,lwd=2,xpd=NA);
        localwin <- which(x>2 & x<3);
        tp <- which.min(abs(diff(y[localwin])));
        if (length(tp)>0L) points(x[localwin[tp]],y[localwin[tp]],col=col,pch=4L);
        localwin <- which(x>2 & x<5);
        tp <- which.min(diff(y[localwin]));
        if (length(tp)>0L) {
            m <- diff(y[localwin[seq(tp,len=2L)]])/diff(x[localwin[seq(tp,len=2L)]]);
            if (is.finite(m)) abline(y[localwin[tp]]-m*x[localwin[tp]],m,col=col,lty=2L);
        };
    });
};

1 个答案:

答案 0 :(得分:1)

这是我如何做到的,你可以玩漂亮的标签(参见函数?pretty)。我改变的部分周围有空格。请注意,这不是C,因此;不是必需的。放置一些空格和命名参数会使代码更具可读性。

effCis <- grep('^efficiency',names(mydf));
find.measurements <- grep("^measurement", names(mydf))

xlim <- c(1,length(effCis));
ylim <- range(mydf[,effCis],na.rm=T);
ylim[1L] <- floor(ylim[1L]/0.1)*0.1;
ylim[2L] <- ceiling(ylim[2L]/0.1)*0.1;
yticks <- seq(ylim[1L],ylim[2L],0.1);

xticks <- seq(from = min(mydf[, find.measurements]), to = max(mydf[, find.measurements]), length.out = 7)

plot(NA,xlim=c(min(xticks), max(xticks)), ylim=ylim,xlab='measurement',ylab='efficiency',xaxs='i',yaxs='i',axes=F)

abline(v=xticks,col='lightgrey');
abline(h=yticks,col='lightgrey');
abline(h=0,lwd=2);

axis(side = 1, at = xticks)

axis(2L,yticks,sprintf('%.1f',yticks),las=1L,font=2L,cex.axis=0.7);
hybrid.col <- data.frame(hybrid=seq_len(nrow(mydf)),col=c('red','green','blue','gold','cyan','magenta'),stringsAsFactors=F);
splineN <- 200L;
for (ri in seq_len(nrow(hybrid.col))) {
  hybrid <- hybrid.col$hybrid[ri];
  col <- hybrid.col$col[ri];
  x <- xticks;
  y <- c(as.matrix(mydf[hybrid,effCis]));
  points(x,y,pch=16L,col=col,xpd=NA);
  with(spline(x,y,splineN),{
    lines(x,y,col=col,lwd=2,xpd=NA);
    localwin <- which(x>2 & x<3);
    tp <- which.min(abs(diff(y[localwin])));
    if (length(tp)>0L) points(x[localwin[tp]],y[localwin[tp]],col=col,pch=4L);
    localwin <- which(x>2 & x<5);
    tp <- which.min(diff(y[localwin]));
    if (length(tp)>0L) {
      m <- diff(y[localwin[seq(tp,len=2L)]])/diff(x[localwin[seq(tp,len=2L)]]);
      if (is.finite(m)) abline(y[localwin[tp]]-m*x[localwin[tp]],m,col=col,lty=2L);
    };
  });
};

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