我的会计软件中有一个导出的表，如下面SQL Server 2008中那样。
AccountID AccountName SourceCast
--------- ----------- -----------
11 Acc11 9401
12 Acc12 9401
13 Acc13 9401
11/11 Acc11/11 9401
11/12 Acc11/12 9401
11/111 Acc11/111 9401
11/11/001 Acc11/11/001 9401
11/11/002 Acc11/11/002 9401
15 Acc15 9402
12 Acc12 9402
13 Acc13 9402
15/15 Acc15/15 9402
15/12 Acc15/12 9402
15/111 Acc15/111 9402
15/15/001 Acc15/15/001 9402
15/15/002 Acc15/15/002 9402
然后预期结果必须如下：
AccountID AccountName ID ParentID Level HasChild SourceCast
--------- ----------- --- --------- ------ -------- ----------
9401 9401 1 Null 1 1 9401
11 Acc11 2 1 2 1 9401
12 Acc12 3 1 2 1 9401
13 Acc13 4 1 2 0 9401
11/11 Acc11/11 5 2 3 1 9401
11/12 Acc11/12 6 2 3 0 9401
11/111 Acc11/111 7 2 3 0 9401
11/11/001 Acc11/11/001 8 5 4 0 9401
11/11/002 Acc11/11/002 9 5 4 0 9401
12/111 Acc12/111 10 5 3 0 9401
12/112 Acc12/112 11 5 3 0 9401
9402 9402 12 Null 1 1 9401
15 Acc15 13 12 2 1 9402
12 Acc12 14 12 2 1 9402
13 Acc13 15 12 2 0 9402
15/15 Acc15/15 16 13 2 1 9402
15/12 Acc15/12 17 13 2 0 9402
15/111 Acc15/111 18 13 3 0 9402
15/15/001 Acc15/15/001 19 16 4 0 9402
15/15/002 Acc15/15/002 20 16 4 0 9402
12/111 Acc12/111 21 14 3 0 9402
12/112 Acc12/112 22 14 3 0 9402
之前提出的这个问题没有＆＃34; SourceCast＆＃34;此Link中的字段由Shnugo回答。我的主表非常大，有超过30000条记录 你能帮帮我吗？ 感谢。
您可以在此处找到我的样本表：
CREATE TABLE Account(AccountID NVARCHAR(50) NOT NULL PRIMARY KEY
,AccountName NVARCHAR(50) NOT NULL
,SourceCast INTEGER NOT NULL);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11',N'Acc11',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'12',N'Acc12',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'13',N'Acc13',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/11',N'Acc11/11',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/12',N'Acc11/12',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/111',N'Acc11/111',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/11/001',N'Acc11/11/001',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/11/002',N'Acc11/11/002',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15',N'Acc15',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'12',N'Acc12',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'13',N'Acc13',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/15',N'Acc15/15',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/12',N'Acc15/12',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/111',N'Acc15/111',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/15/001',N'Acc15/15/001',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/15/002',N'Acc15/15/002',9402);
答案 0 :(得分：1)
这应该让你非常接近...但我必须承认，我并不完全理解逻辑......为什么9401 / Acc12＆＃34; HasChild＆＃34;设为1？
试试吧。编号由SourceCast划分。这意味着，两个集合（或许多集合都被视为一个集合，具体取决于SourceCast。此外，还有一个正在运行的ID，如您的示例所示：
CREATE TABLE Account(AccountID NVARCHAR(50) NOT NULL
,AccountName NVARCHAR(50) NOT NULL
,SourceCast INTEGER NOT NULL
,PRIMARY KEY (AccountID,SourceCast));
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11',N'Acc11',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'12',N'Acc12',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'13',N'Acc13',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/11',N'Acc11/11',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/12',N'Acc11/12',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/111',N'Acc11/111',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/11/001',N'Acc11/11/001',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'11/11/002',N'Acc11/11/002',9401);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15',N'Acc15',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'12',N'Acc12',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'13',N'Acc13',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/15',N'Acc15/15',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/12',N'Acc15/12',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/111',N'Acc15/111',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/15/001',N'Acc15/15/001',9402);
INSERT INTO Account(AccountID,AccountName,SourceCast) VALUES (N'15/15/002',N'Acc15/15/002',9402);
GO
WITH DistinctSourceCasts AS (SELECT DISTINCT SourceCast FROM Account)
SELECT *
INTO #tempHierarchy
FROM
(
SELECT SourceCast
,CAST(SourceCast AS NVARCHAR(50)) AS AccountID
,CAST(SourceCast AS NVARCHAR(50)) AS AccountName
,0 AS ID
,0 AS HierarchyLevel
,'' AS ParentPath
,'' AS ownID
,'' AS ancestorID
FROM DistinctSourceCasts
UNION ALL
SELECT SourceCast
,AccountID
,AccountName
,ROW_NUMBER() OVER(PARTITION BY SourceCast ORDER BY LEN(AccountID)-LEN(REPLACE(AccountID,'/','')),AccountID) AS ID
,Extended.HierarchyLevel
,STUFF(
(
SELECT '/' + A.B.value('.','varchar(10)')
FROM Extended.IDsXML.nodes('/x[position() <= sql:column("HierarchyLevel")]') AS A(B)
FOR XML PATH('')
),1,2,'') AS ParentPath
,Extended.IDsXML.value('/x[sql:column("HierarchyLevel")+1][1]','varchar(10)') AS ownID
,Extended.IDsXML.value('/x[sql:column("HierarchyLevel")][1]','varchar(10)') AS ancestorID
FROM Account
CROSS APPLY(SELECT LEN(AccountID)-LEN(REPLACE(AccountID,'/','')) + 1 AS HierarchyLevel
,CAST('<x></x><x>' + REPLACE(AccountID,'/','</x><x>') + '</x>' AS XML) AS IDsXML) AS Extended
) AS tbl;
UPDATE #tempHierarchy SET ParentPath = SourceCast,ancestorID=SourceCast WHERE HierarchyLevel=1;
UPDATE #tempHierarchy SET ownID=SourceCast WHERE HierarchyLevel=0;
WITH RecursiveCTE AS
(
SELECT th.*
,CAST(NULL AS BIGINT) AS ParentID
,CASE WHEN EXISTS(SELECT 1 FROM #tempHierarchy AS x WHERE x.ParentPath=th.AccountID) THEN 1 ELSE 0 END AS HasChild
FROM #tempHierarchy AS th WHERE th.HierarchyLevel=0
UNION ALL
SELECT r.SourceCast
,sa.AccountID
,sa.AccountName
,sa.ID
,sa.HierarchyLevel
,sa.ParentPath
,sa.ownID
,sa.ancestorID
,(SELECT x.ID FROM #tempHierarchy AS x WHERE x.AccountID=sa.ParentPath)
,CASE WHEN EXISTS(SELECT 1 FROM #tempHierarchy AS x WHERE x.ParentPath=sa.AccountID) THEN 1 ELSE 0 END AS HasChild
FROM RecursiveCTE AS r
INNER JOIN #tempHierarchy AS sa ON sa.HierarchyLevel=r.HierarchyLevel+1
AND r.AccountID=sa.ParentPath
AND r.SourceCast=sa.SourceCast
)
SELECT SourceCast
,r.AccountID
,r.AccountName
,ROW_NUMBER() OVER(ORDER BY SourceCast,HierarchyLevel,ParentID,ID) AS ID
,r.ID AS GroupedID
,r.ParentID
,r.HierarchyLevel
,r.HasChild
FROM RecursiveCTE AS r
DROP TABLE #tempHierarchy;
结果：
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| SourceCast | AccountID | AccountName | ID | GroupedID | ParentID | HierarchyLevel | HasChild |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 9401 | 9401 | 1 | 0 | NULL | 0 | 1 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 11 | Acc11 | 2 | 1 | 0 | 1 | 1 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 12 | Acc12 | 3 | 2 | 0 | 1 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 13 | Acc13 | 4 | 3 | 0 | 1 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 11/11 | Acc11/11 | 5 | 4 | 1 | 2 | 1 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 11/111 | Acc11/111 | 6 | 5 | 1 | 2 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 11/12 | Acc11/12 | 7 | 6 | 1 | 2 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 11/11/001 | Acc11/11/001 | 8 | 7 | 4 | 3 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9401 | 11/11/002 | Acc11/11/002 | 9 | 8 | 4 | 3 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 9402 | 9402 | 10 | 0 | NULL | 0 | 1 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 12 | Acc12 | 11 | 1 | 0 | 1 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 13 | Acc13 | 12 | 2 | 0 | 1 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 15 | Acc15 | 13 | 3 | 0 | 1 | 1 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 15/111 | Acc15/111 | 14 | 4 | 3 | 2 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 15/12 | Acc15/12 | 15 | 5 | 3 | 2 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 15/15 | Acc15/15 | 16 | 6 | 3 | 2 | 1 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 15/15/001 | Acc15/15/001 | 17 | 7 | 6 | 3 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+
| 9402 | 15/15/002 | Acc15/15/002 | 18 | 8 | 6 | 3 | 0 |
+------------+-----------+--------------+----+-----------+----------+----------------+----------+