我有powershell脚本来替换程序集版本,但我必须在第三个位置更改版本号 喜欢[assembly:AssemblyVersion(" 1.0.20.1")]来 [assembly:AssemblyVersion(" 1.0.21.1")]
这就是我所拥有的,它增加了最后一个位置:
#
# This script will increment the build number in an AssemblyInfo.cs file
#
$assemblyInfoPath = "C:\Users\kondas\Desktop\PowerShell\AssemblyInfo.cs"
$contents = [System.IO.File]::ReadAllText($assemblyInfoPath)
$versionString = [RegEx]::Match($contents,"(AssemblyFileVersion\("")(?:\d+\.\d+\.\d+\.\d+)(""\))")
Write-Host ("AssemblyFileVersion: " +$versionString)
#Parse out the current build number from the AssemblyFileVersion
$currentBuild = [RegEx]::Match($versionString,"(\.)(\d+)(""\))").Groups[2]
Write-Host ("Current Build: " + $currentBuild.Value)
#Increment the build number
$newBuild= [int]$currentBuild.Value + 1
Write-Host ("New Build: " + $newBuild)
#update AssemblyFileVersion and AssemblyVersion, then write to file
Write-Host ("Setting version in assembly info file ")
$contents = [RegEx]::Replace($contents, "(AssemblyVersion\(""\d+\.\d+\.\d+\.)(?:\d+)(""\))", ("`${1}" + $newBuild.ToString() + "`${2}"))
$contents = [RegEx]::Replace($contents, "(AssemblyFileVersion\(""\d+\.\d+\.\d+\.)(?:\d+)(""\))", ("`${1}" + $newBuild.ToString() + "`${2}"))
[System.IO.File]::WriteAllText($assemblyInfoPath, $contents)
答案 0 :(得分:1)
我个人会用各个部分的值创建一个对象,然后你可以增加你想要的任何部分,然后将它重组成一个字符串。
$Version = $contents | ?{$_ -match 'AssemblyVersion\("(\d+)\.(\d+)\.\(d+)\.(\d+)"\)'}|%{
[PSCustomObject]@{
[int]'First'=$Matches[1]
[int]'Second'=$Matches[2]
[int]'Third'=$Matches[3]
[int]'Fourth'=$Matches[4]
}
}
然后您可以像$Version.Third++
一样简单地增加以增加第三组。然后只需使用格式化的字符串将其吐出:
'AssemblyVersion("{0}.{1}.{2}.{3}")' -f $Version.First, $Version.Second, $Version.Third, $Version.Fourth
这将产生AssemblyVersion("1.0.21.1")
就像你想要的那样。