我想知道,如何从listview和SQLite数据库中删除项目。我有这个代码。我应该更改什么,因为项目没有从列表视图中删除。这是我的整个代码,我不知道该改变什么
DBAdapter.java
static final String ROW_ID ="id";
static final String NAME ="name";
static final String TAG = "DBAdapter";
static final String DBNAME="m_DB";
static final String TBNAME="m_TB";
static final int DBVERSION='1';
static final String CREATE_TB="CREATE TABLE m_TB(id INTEGER PRIMARY KEY AUTOINCREMENT,"
+ "name TEXT NOT NULL);";
final Context c;
SQLiteDatabase db;
DBHelper helper;
public DBAdapter(Context ctx) {
this.c = ctx;
helper = new DBHelper(c);
}
private static class DBHelper extends SQLiteOpenHelper {
public DBHelper(Context context) {
super(context, DBNAME, null, DBVERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
try {
db.execSQL(CREATE_TB);
} catch (SQLException e)
{
e.printStackTrace();
}
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
Log.w("DBAdapter","Upgrading DB");
db.execSQL("DROP TABLE IF EXISTS m_TB");
onCreate(db);
}
}
public DBAdapter openDB()
{
try {
db=helper.getWritableDatabase();
} catch (SQLException e)
{
Toast.makeText(c, e.getMessage(), Toast.LENGTH_LONG).show();
}
return this;
}
public void close()
{
helper.close();
}
public long add(String name)
{
try {
ContentValues cv = new ContentValues();
cv.put(NAME,name);
return db.insert(TBNAME,ROW_ID,cv);
} catch (SQLException e)
{
e.printStackTrace();
}
return 0;
}
public Cursor getAllNames()
{
String[] columns={ROW_ID,NAME};
return db.query(TBNAME,columns,null,null,null,null,null);
}
MainActivity.java
public class MainActivity extends AppCompatActivity {
ListView lv;
EditText nameTxt;
Button savebtn,retrievebtn;
ArrayList<String> books = new ArrayList<String>();
ArrayAdapter<String> adapter;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
nameTxt=(EditText)findViewById(R.id.editText);
savebtn=(Button)findViewById(R.id.saveBtn);
retrievebtn=(Button)findViewById(R.id.retrieveBtn);
lv = (ListView)findViewById(R.id.listView1);
adapter = new ArrayAdapter<String>(this,android.R.layout.simple_selectable_list_item,books);
final DBAdapter db = new DBAdapter(this);
savebtn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
db.openDB();
long result = db.add(nameTxt.getText().toString());
if(result > 0)
{
nameTxt.setText("");
}else
{
Toast.makeText(getApplicationContext(),"Failure", Toast.LENGTH_SHORT).show();
}
db.close();
}
});
retrievebtn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
books.clear();
db.openDB();
Cursor c = db.getAllNames();
while (c.moveToNext())
{
String name = getString(1);
books.add(name);
}
lv.setAdapter(adapter);
db.close();
}
});
lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
Toast.makeText(getApplicationContext(),books.get(position), Toast.LENGTH_SHORT).show();
}
});
}
public void onCreateContextMenu(ContextMenu menu, View v,
ContextMenu.ContextMenuInfo menuInfo)
{
super.onCreateContextMenu(menu,v,menuInfo);
menu.add("Delete");
}
public boolean onContextItemSelected(MenuItem item)
{
super.onContextItemSelected(item);
if(item.getTitle()== "Delete")
{
books.remove(item);
adapter.notifyDataSetChanged();
}
return true;
}
我将其插入DPAdapter
public void delete(String name)throws SQLException {
SQLiteDatabase db = helper.getWritableDatabase();
if (db == null) {
return;
}
String[] whereArgs = new String[] { name };
db.delete(TBNAME, NAME+ "=?", whereArgs);
db.close();
}
和MainActivity
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu,v,menuInfo);
menu.add("Delete");
}
public boolean onContextItemSelected(MenuItem item) {
super.onContextItemSelected(item);
AdapterView.AdapterContextMenuInfo info = (AdapterView.AdapterContextMenuInfo) item.getMenuInfo();
String name = info.toString();
if (item.getTitle().equals("Delete")) {
db.delete(name);
books.remove(item);
adapter.notifyDataSetChanged();
}
return true;
}
但没有发生任何事情。我怎么称呼删除方法?
答案 0 :(得分:1)
将字符串与.equals比较而不是&#34; ==&#34; :
if(item.getTitle().equals("Delete"))
{
books.remove(item);
adapter.notifyDataSetChanged();
}
您还需要添加删除查询以从SQlite中删除项目,因为您目前只从列表视图中删除项目。
答案 1 :(得分:1)
这是您从SQLite Database
删除项目的方法,您需要将其添加到DBAdapter
。
public void delete(String name)throws SQLException {
SQLiteDatabase db = _openHelper.getWritableDatabase();
if (db == null) {
return;
}
String[] whereArgs = new String[] { name };
db.delete("YOUR_TABLE_NAME", "COLUMN_NAME"+ "=?", whereArgs);
db.close();
}
并从ListView
中删除它,您需要从列表中删除项目,然后通知您的适配器
YourArraylist.remove([index]);
YourAdapter.notifyDataSetChanged();