Question

我的zip文件里面有几个文件。当我运行我的解压缩代码时：

public ArrayList<String> unzip(String zipFilePath, String destDirectory, String filename) throws IOException {
        ArrayList<String> pathList = new ArrayList<String>();
        File destDir = new File(destDirectory);
        if (!destDir.exists()) {
            destDir.mkdir();
        }
        ZipInputStream zipIn = new ZipInputStream(new FileInputStream(zipFilePath));
        ZipEntry entry = zipIn.getNextEntry();
        // iterates over entries in the zip file
        while (entry != null) {
            //          Original file name  
            //          String filePath = destDirectory + File.separator + entry.getName();
            int _ordPosition = entry.getName().indexOf("_ord");
            if (_ordPosition<0)
                throw new DatOrderException("Files inside zip file are not in correct format (please order them with _ordXX string)");
            String ord = entry.getName().substring(_ordPosition,_ordPosition+6); 
            String filePath = destDirectory + File.separator + filename + ord + "."+ FilenameUtils.getExtension(entry.getName());
            if (!entry.isDirectory()) {
                // if the entry is a file, extracts it
                pathList.add(filePath);
                extractFile(zipIn, filePath);
            } else {
                // if the entry is a directory, make the directory
                File dir = new File(filePath);
                dir.mkdir();
            }
            zipIn.closeEntry();
            entry = zipIn.getNextEntry();
        }
        zipIn.close();
        return pathList;
    }

如果档案内的文件包含特殊字符，例如º我收到行格式错误消息的异常

ZipEntry entry = zipIn.getNextEntry();

是否可以重命名此文件或修复此错误？感谢

Answer 1

尝试使用正确的字符编码读取zip文件 - 使用ZipInputStream（java.io.InputStream，java.nio.charset.Charset）而不是ZipInputStream（java.io.InputStream）

Answer 2

正如@Andrew Kolpakov建议的那样，

 ZipInputStream zipIn = new ZipInputStream(new FileInputStream(zipFilePath),Charset.forName("IBM437"));

似乎有效

通过java.util.zip库解压缩具有特殊字符的文件

2 个答案: