我的代码从* .mtx文件读取稀疏矩阵,并应在控制台上打印矩阵(仅用于测试,对于实际情况我想返回稀疏矩阵),但他打印的地址不是值。
我的代码:
#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <fstream>
#include <algorithm>
using namespace std;
struct MatriceRara
{
int *Linie, *Coloana, *Valoare;
int nrElemente, nrLinii, nrColoane;
};
MatriceRara Read(const char* mtx) {
const char * mtx_file = mtx;
ifstream fin(mtx_file);
MatriceRara matR;
int nrElemente, nrLinii, nrColoane;
// skip header:
while (fin.peek() == '%') fin.ignore(2048, '\n');
// read parameters:
fin >> nrLinii >> nrColoane >> nrElemente;
matR.nrElemente = nrElemente;
matR.nrLinii = nrLinii;
matR.nrColoane = nrColoane;
cout << "Number of rows: " << matR.nrLinii <<endl;
cout << "Number of columns: " << matR.nrColoane << endl;
cout << "Number of not null values: " << matR.nrElemente << endl;
for (int i = 0; i< nrElemente; i++)
{
int *m ,*n,*data;
fin >> (int &) m >> (int &) n >> (int &) data;
matR.Linie = m;
matR.Coloana = n;
matR.Valoare = data;
//only for test:
cout<<matR.Linie << " " << matR.Coloana << " " << matR.Valoare <<endl;
}
//return matR;
}
int main () {
MatriceRara a = Read("Amica.mtx");
}
我的输出:
Number of rows: 5
Number of columns: 5
Number of not null values: 8
0x7fff00000001 0x7f4400000001 0x1
0x7fff00000000 0x7f4400000001 0x1
0x7fff00000000 0x7f4400000001 0x1
0x7fff00000000 0x7f4400000001 0x1
0x7fff00000000 0x7f4400000001 0x1
0x7fff00000000 0x7f4400000001 0x1
0x7fff00000000 0x7f4400000001 0x1
0x7fff00000000 0x7f4400000001 0x1
因此,正如您在我的输出中所看到的,它打印的是地址,而不是值。 非常感谢!
答案 0 :(得分:4)
您将以下成员声明为int:
的指针int *Linie, *Coloana, *Valoare;
然后你打印这些指针:
cout<<matR.Linie << " " << matR.Coloana << " " << matR.Valoare <<endl;
所以你得到你所问的:指针的值(例如地址)
答案 1 :(得分:1)
因为变量Linie
,Coloana
和Valoare
是指针。
您必须在*
之前取消引用指针。
int value;
value = *m;
如果你想打印这些值,请再次在这里:
cout<< *matR.Linie << " " << *matR.Coloana << " " << *matR.Valoare << endl;
答案 2 :(得分:-4)
类型int *
的所有变量和类成员都应该是int
类型。目前它们是未初始化的指针,而它们实际上是整数。