通缉效果是将id传递给请求处理程序并使用该实体填充表单。模板的可行性如何?这是我的表单,请求处理程序和模板
class AForm(djangoforms.ModelForm):
text = forms.CharField(widget=forms.Textarea(attrs={'rows':'11','cols':'70','class':'foo'}),label=_("content").capitalize())
class Meta:
model = A
fields = ['category','currency','price','title','phonenumber','postaladress','name','text','email'] #change the order
class FileUploadFormHandler(I18NHandler):
def get(self):
cookie_django_language = self.request.get('hl', '')
if cookie_django_language:
if cookie_django_language == 'unset':
del self.request.COOKIES['django_language']
else:
self.request.COOKIES['django_language'] = cookie_django_language
translation.activate(cookie_django_language)
self.render_template("upload.html", {
'form': AForm(),
'form_url': blobstore.create_upload_url('/fileupload'),
'logout_url': users.create_logout_url('/'),
})
<table>
{% for field in form %}
<tr><td>
<div class="fieldWrapper">
{{ form.title.errors }}
<label for="id_subject">{% filter capfirst %}{% trans "headline" %}{% endfilter %}</label></td><td>
{{ form.title }}</td></tr>
</div><tr><td>
<div class="fieldWrapper">
{{ form.category.errors }}
<label for="id_subject">{% filter capfirst %}{% trans "content" %}{% endfilter %}</label></td><td>
答案 0 :(得分:3)
您应该使用要显示的实体初始化表单:
form = AForm(instance = some_model_instance)