codeigniter

时间:2016-04-29 06:46:50

标签: php html codeigniter

我仍然在CodeIgniter中学习。

我想在我的codeigniter应用程序中创建一个登录表单。 我的观点部分如下:

<html>
  <head>    
    <title>Jotorres Login Screen | Welcome </title>
  </head>
  <body>
    <div id='login_form'>
      <form action="<?php echo base_url();?>Login/process" method='post' name='process' enctype="multipart/form-data">
        <h2>User Login</h2>
        <br />  
        <?php if(! is_null($msg)) echo $msg;?>   
        <label for='username'>Username</label>
        <input type='text' name='username' id='username' size='25' /><br />
        <label for='password'>Password</label>
        <input type='password' name='password' id='password' size='25' /><br />                            
        <input type='Submit' value='Login' />            
     </form>
    </div>
  </body>
</html>

控制器部分:

<?php

  if ( ! defined('BASEPATH')) exit('No direct script access allowed');
  /* Author: Jorge Torres
  * Description: Login controller class
  */
  {
    class Login extends CI_Controller{

      function __construct(){
          parent::__construct();
      }


      public function index($msg = NULL){
          // Load our view to be displayed
          // to the user
          $data['msg'] = $msg;
          $this->load->view('login_view', $data);
      }


      public function process(){
          // Load the model
          $this->load->model('login_model');
          // Validate the user can login
          $result = $this->login_model->validate();
          // Now we verify the result
          if(! $result){
              // If user did not validate, then show them login page again
              $msg = '<font color=red>Invalid username and/or password.</font><br />';
              $this->index($msg);
          }else{
              // If user did validate, 
              // Send them to members area
              redirect('Home');
          }        
      }
    }
  }
?>

错误讯息:

  

在此服务器上找不到请求的URL / afi /登录/进程。

如何解决此错误?

模型部分:

<?php
defined('BASEPATH') OR exit('No direct script access allowed');
/* Author: Jorge Torres
 * Description: Login model class
 */
class Login_model extends CI_Model{
    function __construct(){
        parent::__construct();
    }

    public function validate(){
        // grab user input
        $username = $this->security->xss_clean($this->input->post('username'));
        $password = $this->security->xss_clean($this->input->post('password'));

        // Prep the query
        $this->db->where('username', $username);
        $this->db->where('password', $password);

        // Run the query
        $query = $this->db->get('users');
        // Let's check if there are any results
        if($query->num_rows == 1)
        {
            // If there is a user, then create session data
            $row = $query->row();
            $data = array(
                    'userid' => $row->userid,
                    'fname' => $row->fname,
                    'lname' => $row->lname,
                    'username' => $row->username,
                    'validated' => true
                    );
            $this->session->set_userdata($data);
            return true;
        }
        // If the previous process did not validate
        // then return false.
        return false;
    }
}
?>

3 个答案:

答案 0 :(得分:1)

在模型中将 <input name="searchText" value={searchText} onChange={this.onChange} /> <div className="col s12"> <input name="searchText" value={searchText} onChange={this.onChange} /> </div> 替换为$query->num_rows,然后重试。

答案 1 :(得分:0)

尝试使用site_url()。 改变:

  

<form action="<?php echo base_url();?>Login/process" method='post' name='process' enctype="multipart/form-data">

到:

  

<form action="<?php echo site_url('Login/process');?>" method='post' name='process' enctype="multipart/form-data">

base_url产生:

  

http://localhost/codeigniter/

site_url产生:

  

http://localhost/codeigniter/index.php

答案 2 :(得分:0)

尝试一下  <?php echo form_open('Login/process')?> 解决问题的最佳方法