我想将我的代码序列化为XML。
现在我有:
var exist = true;
function checkAccountSuspension() {
var accountNumberId = $('#DepositAccountNumberIdHiddenField').val();
if (accountNumberId == "") {
//
} else {
try {
var url = '/WebMethods/AccountDetails.asmx/IsAccountSuspended';
var d = { accountNumberId: accountNumberId };
//$.post(url, d, function (data) {
var jqXhr = ajaxPost(url, d, true);
jqXhr.done(function (data) {
var ret = data.d;
if (!ret) {
$('#DepositAccountNumberIdHiddenField').val(accountNumberId);
exist = true;
}
else {
//$('#DepositAccountNumberIdHiddenField').val('');
// bootbox.alert("<b class='text-red'>Suspended Account</b> <br/>This Account has been Suspended.");
swal({
title: "Suspended Account!",
text: "This Account is Suspended",
type: "error",
confirmButtonText: "OK",
imageSize: "20x20"
});
exist = false;
resetAllInputs();
}
}).fail(function (ex) {
bootbox.alert("Requested process fail to execute");
//$('#DepositAccountNumberIdHiddenField').val('');
});
}
catch (e) {
bootbox.alert('Error: ' + e);
}
}
}
我的C#代码如下:
<?xml version="1.0" encoding="utf-8"?>
<SerializationClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Value>Test</Value>
</SerializationClass>
但我想要像XML一样:
public class SerializationClass
{
[XmlElement("Value")]
public string City { get; set; }
}
答案 0 :(得分:1)
您无法使用您拥有的类结构(无需手动编码)。如果您愿意更改结构,这将有效:
public class SerializationClass
{
public City City { get; set; }
}
public class City
{
[XmlAttribute("value")]
public string Value { get; set; }
}
答案 1 :(得分:0)
这种做法怎么样?
public class SerializationClass
{
[XmlIgnore]
public string City { get; set; }
[EditorBrowsable(EditorBrowsableState.Never)]
[XmlAnyElement]
public XElement _City
{
get { return new XElement("City", new XAttribute("value", City)); }
set { City = value.FirstAttribute.Value; }
}
}