我想选择表格的最后一行,并将所有值保存到单独的JavaScript变量中。我在PHP中使用了查询:
import java.util.Scanner;
public class Project4JamesVincent {
public static void main(String []args){
Scanner input = new Scanner(System.in);
System.out.print("Enter the size of the arrays: ");
int size = input.nextInt();
System.out.println();
System.out.println("Enter " + size + " items for array X: ");
double[] arrayX = createArray(size, input);
System.out.println();
System.out.println("Enter " + size + " items for array Y: ");
double[] arrayY = createArray(size, input);
System.out.print("The distance between x and y is: ");
double totalDistance = 0;
for (int i = 0; i<size; i++){
totalDistance = totalDistance + Math.abs((arrayX[i]-arrayY[i]));
}
double averageDistance = 0;
averageDistance = (totalDistance/size);
System.out.printf("%3.2f", averageDistance);
}
public static double[] createArray (int n, Scanner enter){
double[] tempArray = new double[n];
for (int i=0; i<tempArray.length; i++){
tempArray[i] = enter.nextDouble();
}
return tempArray;
}
}
选择表格的最后一行。我不知道该怎么办。
答案 0 :(得分:2)
PHP:
$sql = "SELECT * from reading ORDER BY id DESC LIMIT 1";
if ($query = mysqli_query($link, $sql)) {
// fetch one result
$row = mysqli_fetch_row($query);
echo json_encode($row);
}
jQuery的:
// sample variables
var username = "";
var password = "";
var phpUrl = 'http://sampleurl.com/mypage.php';
$.getJSON(phpUrl, function (result) {
$.each(result, function (data) {
// if data sent back is eg data:[{username:'sample', password:'sample'}]
// then you fetch and save as
username = data.username;
password = data.password;
});
});
答案 1 :(得分:0)
cookies方式绝对是要走的路。如果您在一个页面上完成所有这些操作,只需要快速修复即可
<?php
$sql = "SELECT * from reading ORDER BY id DESC LIMIT 1";
if ($query = mysqli_query($link, $sql)) {
// fetch one result
$row = mysqli_fetch_row($query);
$json_string = json_encode($row);
}
?>
<script> var sql_row = <?php echo $json_string; ?>; </script>
这是一种懒惰的方式,很快就会变得混乱,但它对于理解PHP和JS如何协同工作非常有用