编译代码

Question

我已经完成了一些java编码，但我对c ++完全不熟悉，并且不知道我的代码现在正在进行什么。此代码在地图标准库中给出了编译错误。它说：Cannot increment value of type ' std::_1::pari<int, int>'，并且发生在map，insert(_InputIterator __f, _InputIterator __l)，如果有任何相关性的话。

我知道stackoverflow社区通常不喜欢解决其他人的家庭作业，但我认为我做了一个真正的尝试来实现这一点，除此之外，我对于发生了什么感到非常好奇

typedef std::pair<int, int> location;

std::set<location> neighbours(location loc, std::set<std::pair<location, location>> labyrinth, int& size) {
    std::set<location> neighbours;
    location locFmin = location(loc.first - 1, loc.second);
    location locSmin = location(loc.first, loc.second - 1);
    location locFplus = location(loc.first + 1, loc.second);
    location locSplus = location(loc.first, loc.second + 1);

    if (loc.first - 1 >= 0 && labyrinth.find(std::pair<location, location>(loc, locFmin)) == labyrinth.end()) {
        neighbours.insert(locFmin);
    }
    if (loc.second - 1 >= 0 && labyrinth.find(std::pair<location, location>(loc, locSmin)) == labyrinth.end()) {
        neighbours.insert(locSmin);
    }
    if (loc.first + 1 < size && labyrinth.find(std::pair<location, location>(loc, locFplus)) == labyrinth.end()) {
        neighbours.insert(locFplus);
    }
    if (loc.second + 1 < size && labyrinth.find(std::pair<location, location>(loc, locSplus)) == labyrinth.end()) {
        neighbours.insert(locSplus);
    }

    return neighbours;
}

int Labyrinth(std::set<std::pair<location, location>> labyrinth, int size) {
    std::map<location, location> forest;
    std::set<location> level;
    std::set<location> known;

    known.insert(location(0,0));
    level.insert(location(0,0));

    while (!level.empty()) {
        std::set<location> nextLevel;
        for (location loc: level) {
            for (location neighbour: neighbours(loc, labyrinth, size)) {
                if (known.find(neighbour) != known.end()) {
                    known.insert(neighbour);
                    forest.insert(neighbour, loc);
                    nextLevel.insert(neighbour);
                }
            }
        }
        level = nextLevel;
    }

    std::list<location> path;
    location walk = location(size - 1, size - 1);
    path.push_front(walk);
    while (walk != location(0, 0)) {
        walk = forest[walk];
        path.push_front(walk);
    }

    int answ = path.size();

    return answ;
}

这是一种算法，它应该通过大小为size的方形迷宫执行广度优先搜索，当然大小为* location(x, y)个对象。 传入列表labyrinth定义了无法通过的迷宫墙。最终，该函数应该返回从（0,0）到（size-1，size-1）的最短路径中包含的节点数。

这是算法的简单测试

std::set<std::pair<location, location> > labyrinth;
    labyrinth.insert(std::pair<location, location>(location(0, 0), location(1, 0)));
    labyrinth.insert(std::pair<location, location>(location(0, 1), location(1, 1)));
    labyrinth.insert(std::pair<location, location>(location(0, 2), location(0, 3)));
    labyrinth.insert(std::pair<location, location>(location(1, 1), location(1, 2)));
    labyrinth.insert(std::pair<location, location>(location(1, 2), location(2, 2)));
    labyrinth.insert(std::pair<location, location>(location(2, 3), location(3, 3)));
    labyrinth.insert(std::pair<location, location>(location(2, 2), location(3, 2)));
    labyrinth.insert(std::pair<location, location>(location(2, 1), location(3, 1)));

    int labAnswer = Labyrinth(labyrinth, 4);
    std::cout << labAnswer << std::endl;
    if (labAnswer == 13)
    {
        std::cout << "Correct" << std::endl;
    }
    else
    {
        std::cout << "Incorrect" << std::endl;
    }

在任何人开始提出更好的想法来解决这个问题之前。我从一本关于算法的书中得到了关于bfs java实现的bfs代码的想法。我对更有效地解决这个难题并不感兴趣，总会有更好的方法来做某事。我想知道我的代码发生了什么，可能还有我在这里缺少的c ++方面。

Answer 1

你没有正确使用std :: map和insert，

行

forest.insert(neighbour, loc);

应该是

forest[neighbor] = loc;

Answer 2

检查#include标题，您需要

#include <map>

此外，如果您添加using namespace std;，则可以跳过为每个声明添加std::。